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4 years ago

5

A specific example of how light year is used in space exploration. Pick one object in space (the nearest star, the nearest galax

y, the edge of the universe, etc.) and tell how far this object is from earth and how long it would take light to travel there.

1 answer:

VladimirAG [237]4 years ago

5 0

Alpha Centauri A is about 93 million miles away from the Earth and it takes light 4.367 years to reach there.

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The motion of a car on a position time graph is represented with a horizontal tine What does this indicate about the car's motio

GalinKa [24]

Answer:

Position-Time graphs display the motion of a object by showing the changes of velocity with respect to time.

The motion of a car on a position-time graph that is represented with a horizontal line indicates that the car has stopped moving.

A straight line with a positive slope indicates that the car is moving at a constant velocity, and thus the slope is constant. On the other hand, a curve with a changing slope, shows that the velocity is changing.

8 0

3 years ago

Which of the following is NOT accelerating?

ivolga24 [154]

I would say the answer to your question is A Ferris wheel turning at a constant speed. The reasoning behind this answer is the fact that traveling in a constant direction at a constant speed is not accelerating. The Ferris wheel is the only option that fits this description. The last option would be incorrect due to independent causes such as speed limit changes as well as turns and stops on the highway.

7 0

3 years ago

A charge of 90 C passes through a wire in 1 hour 15 minutes . what is the current in the wire

timurjin [86]

We calculate current from the formula:
$I= \frac{q}{t}$ , where q is a electric charge transferred over time t
Time should be converted to seconds:
1h 15 min= 75min= 4500s
I= $\frac{90C}{4500s}=0,02A$ Result is in unit-Ampere

5 0

3 years ago

Read 2 more answers

The atomic radius of metal X is 1.20 × 102 picometers (pm) and a crystal of metal X has a unit cell that is face-centered cubic.

dmitriy555 [2]

The density of the metal can be determined through the formula [n*MW]/ Na*[a^3] . substituting, we get,

<span>d = [n*MW]/ Na*[a^3]
</span><span>d = [4 atoms*42.3 g/mol]/ [6.022 x 1023atoms/mol* (sqrt 8 *1.20x10-10)^3]
</span>d = 0.719 g/cm3

4 0

4 years ago

a 55.0 kg person having a denity of 1010 kg/m^3 is underwater. What is the net force acting on the person?

bija089 [108]

Answer:

The net force acting on the person is 5.34 N acting upwards

Explanation:

The information given are;

Mass of the person = 55.0 kg

Density of the person = 1010 kg/m³

Body volume of the person = Mass/Density = 55/1010 = 0.0545 m³

Weight of the person = Mass × Gravity = 55 × 9.81 = 539.55 N↓

Where the density of water = 1000 kg/m³, we have;

Upthrust = weight of the water displaced = Mass of the water displaced × Gravity

Mass of the water displaced = Density of water × Volume of the water

Mass of the water displaced = Density of water × Body volume of the person

= 1000 × 0.0545 = 54.5 kg

The Upthrust = 54.5 × 9.81 = 534.21 N↑

Given that the net force, $F_{Net}$ acting is the sum of the mass of forces acting on the person which are the weight acting downward and the upthrust acting upwards

We have;

F(Net) = 534.21↑ - 539.55↓ = 5.34 N↑

The net force acting on the person = 5.34 N upwards.

6 0

3 years ago