Answer:
x²+6x+5=0
On comparing with the equation
ax² + bx + c = 0
a=1, b = 6 and c = 5
Now
b²– 4ac = 6² – 4 x 1 x 5 = 36 - 20 = 16
Answer: 724.71 grams
Explanation:
Volume of solution (v) = 5.1 liters
Concentration of solution (c) = 1.4M
Amount of CuF2 needed (n) = ?
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
make n the subject formula
n = c x v
n = 1.4M x 5.1 Liters
n = 7.14 moles
Since, 7.14 moles of CuF2 (n) is needed, use the molar mass of CuF2 to get the mass in grams.
The atomic masses of Copper = 63.5g;
and Fluorine = 19g
So, I CuF2 = 63.5g + (19g x 2)
= 63.5g + 38g
= 101.5g/mol
Then, apply the formula
Number of moles = mass in grams / molar mass
7.14 moles = m / 101.5 g/mol
m = 7.14 moles x 101.5 g/mol
m = 724.71g
Thus, 724.71 grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution
Answer:
Balanced reaction: 
S is oxidized and N is reduced.
is the oxidizing agent and ZnS is the reducing agent.
Explanation:
Reaction: 
Oxidation: 
Balance charge: 
...............(1)
Reduction: 
Balance H and O in acidic medium : 
Balance charge: 
...............(2)
[
Equation-(1)] + [ 
Equation-(2)]:
Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.
Oxidation number of N decreases from (+5) to (+2) for the conversion of to NO. Therefore N is reduced.
consumes electron from ZnS. Therefore is the oxidizing agent and ZnS is the reducing agent.
Answer: 
for the given reaction is 130.19kJ/mol
Explanation:
To Calculate the , we use the formula:
For the given chemical reaction:
We are given:
Now, to calculate , we put the values in the above equation:
As, the value of 
comes out to be positive, the reaction is said to be non-spontaneous reaction.
