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Andrew [12]
3 years ago
9

For calcium and chlorine i need the oxidation number the chemical formula and drawn model!

Chemistry
2 answers:
Mrac [35]3 years ago
8 0
Chlorine oxidation #: -1 
calcium oxidation#: +2

PilotLPTM [1.2K]3 years ago
3 0
Ca = +2
Cl = -1
CaCl₂
Cl-Ca-Cl
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Which hydrocarbon belongs to the Alkyne homologous series?
Ira Lisetskai [31]

Answer:

(A) CHCH

Explanation:

Hello,

Alkynes are formed when triple bonds are formed between carbons, it means that due to the triple bonds, three bonds are already exhausted and carbon atoms need four bonds to attain the octet, for that reason, an extra bond is allowed. Now, such extra bond, when talking about hydrocarbons is filled with hydrogens, for that reason the alkyne should be (A) CHCH as it also accomplishes the following formula which is not accomplished by the rest of the options:

C_nH_{2n-2}

Since n=2, we have:

C_2H_2

Which matches with CHCH.

Best regards.

3 0
3 years ago
How does the mass of an oxygen nucleus
nataly862011 [7]

Answer: The mass of the nucleus is less than the mass of the 8 protons and 8 neutrons.

Explanation:

5 0
3 years ago
Calculate the freezing point of a solution that contains 8.0 g of sucrose (c12h22o11) in 100 g of h2o. kf for h2o = 1.86c/m
Sever21 [200]
Answer is: the freezing point of the solution of sucrose is -0.435°C.
m(H₂O) = 100 g ÷ 1000 g/kg = 0.1 kg.
m(C₁₂H₂₂O₁₁) = 8.0 g. 
n(C₁₂H₂₂O₁₁) = m(C₁₂H₂₂O₁₁) ÷ M(C₁₂H₂₂O₁₁).
n(C₁₂H₂₂O₁₁) = 8.0 g ÷ 342.3 g/mol.
n(C₁₂H₂₂O₁₁) = 0.0233 mol.
b(solution) = n(C₁₂H₂₂O₁₁) ÷ m(H₂O).
b(solution) = 0.0233 mol ÷ 0.1 kg.
b(solution) = 0.233 m.
ΔT = b(solution) · Kf(H₂O).
ΔT = 0.233 m · 1.86°C/m.
ΔT = 0.435°C.
Tb = 0°C - 0.435°C = -0.435°C.
3 0
3 years ago
How many significant figures are in the following numbers?<br> a. 0.002849<br> b. 40030
Kamila [148]
What numbers?......


Explaination:
7 0
3 years ago
14. A 500.0 ml flask contained O2 gas at 25.0°C at a pressure of 4.5 atm. What is the number
Luden [163]

Explanation:

3.Apply the ideal gas law: PV = nRT solving for n. Here you can use the pressure given in atm, but you must choose the 0.0821 atm L/mole K gas constant. Or you can change 4.5 atm to 3420 mm Hg and use the 62.4 mmHg L/mole K gas constant. You must change 500 ml to 0.5 L because both gas constants have units in L, and so the volume must be in liters so it can cancel out. And of course, you must change the temperature to Kelvin.

a. n = (4.5atm)(0.5L)

moliK)(298K) = 0.092 mole (0.0821 atmiL

b. 0.092mol 32g

⎛⎝⎜ ⎞⎠⎟ = 2.9 g

1mol

c. Remember that D = mass

vol so D = 2.9g

0.5L = 5.9 g/L

7 0
3 years ago
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