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algol13
3 years ago
12

List the specific sources of non renewable energy used in 2006

Chemistry
1 answer:
blsea [12.9K]3 years ago
8 0

A list of specific sources of non renewable energy used in 2006 are

- Petroleum[these are natural gases and oils] (28%)

-  Natural gases (31.8%)

- coal (17.8%)

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A buffer contains the weak acid HA and its conjugate base A-. the weak acid has a p Ka of 4.82 and the buffer has a pH of 4.25.
klasskru [66]
<span>I think the correct answer is A. A buffer is a substance that resists small change in the acidity of a solution when an acid or base is added to the solution. Usually, a buffer involves a weak acid or a weak alkali and one of its salt.</span>
3 0
2 years ago
Zinc metal and aqueous silver nitrate react to give Zn(NO3)2(aq) plus silver metal. When 5.00 g of Zn(s) and solution containing
Fittoniya [83]

Answer : The percent yield is, 83.51 %

Solution : Given,

Mass of Zn = 5.00 g

Mass of AgNO_3 = 25.00 g

Molar mass of Zn = 65.38 g/mole

Molar mass of AgNO_3 = 168.97 g/mole

Molar mass of Ag = 107.87 g/mole

First we have to calculate the moles of Zn and AgNO_3.

\text{ Moles of }Zn=\frac{\text{ Mass of }Zn}{\text{ Molar mass of }Zn}=\frac{5.00g}{65.38g/mole}=0.0765moles

\text{ Moles of }AgNO_3=\frac{\text{ Mass of }AgNO_3}{\text{ Molar mass of }AgNO_3}=\frac{25.00g}{168.97g/mole}=0.1479moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

Zn+2AgNO_3\rightarrow Zn(NO_3)_2+2Ag

From the balanced reaction we conclude that

As, 2 mole of AgNO_3 react with 1 mole of Zn

So, 0.1479 moles of AgNO_3 react with \frac{0.1479}{2}=0.07395 moles of Zn

From this we conclude that, Zn is an excess reagent because the given moles are greater than the required moles and AgNO_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Ag

From the reaction, we conclude that

As, 2 mole of AgNO_3 react to give 2 mole of Ag

So, 0.1479 moles of AgNO_3 react to give 0.1479 moles of Ag

Now we have to calculate the mass of Ag

\text{ Mass of }Ag=\text{ Moles of }Ag\times \text{ Molar mass of }Ag

\text{ Mass of }Ag=(0.1479moles)\times (107.87g/mole)=15.95g

Theoretical yield of Ag = 15.95 g

Experimental yield of Ag = 13.32 g

Now we have to calculate the percent yield.

\% \text{ yield}=\frac{\text{ Experimental yield of }Ag}{\text{ Theretical yield of }Ag}\times 100

\% \text{ yield}=\frac{13.32g}{15.95g}\times 100=83.51\%

Therefore, the percent yield is, 83.51 %

7 0
2 years ago
If 0.5 moles of Aluminum react, how many grams of Aluminum Oxide are produced?
Marysya12 [62]

Answer:

210438+28+5+8+2+2+8+30+5+8+6+8+2+5+3+82+8+9+2+8+8+5+5+5+6+9+2+56+5+6+5+-3+8+8+58+5+6+8+5+8+5+35+6+3+8+5+3+68+6+8+6+88+8+!?=8+5+55+5+5+5+5+5+5+5+5+5+2+58+0+80=0=0=00=

3 0
3 years ago
Which of these reactions successfully models a nuclear fission reaction?
user100 [1]

Answer:

OPTION B

Explanation:

Nuclear "fission" is the breakdown of the nucleus of a radioactive element into two or more nuclei accompanied by the release of energy. I guess that pretty much explains it.

3 0
2 years ago
Which word is used describe someone who is fair and has no bias?
rodikova [14]
Impartial is the word that you want to use
6 0
2 years ago
Read 2 more answers
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