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andreev551 [17]
1 year ago
8

Which pair of aqueous solutions can create a buffer solution if present in the appropriate concentrations?.

Chemistry
1 answer:
Julli [10]1 year ago
8 0

HF and NaF - If the right concentrations of aqueous solutions are present, they can produce a buffer solution.

<h3>What are buffer solutions and how do they differ?</h3>
  • The two main categories of buffers are acidic buffer solutions and alkaline buffer solutions.
  • Acidic buffers are solutions that contain a weak acid and one of its salts and have a pH below 7.
  • For instance, a buffer solution with a pH of roughly 4.75 is made of acetic acid and sodium acetate.
<h3>Describe buffer solution via an example.</h3>
  • When a weak acid or a weak base is applied in modest amounts, buffer solutions withstand the pH shift.
  • A buffer made of a weak acid and its salt is an example.
  • It is a solution of acetic acid and sodium acetate CH3COOH + CH3COONa.

learn more about buffer solutions here

<u>brainly.com/question/8676275</u>

#SPJ4

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Please show work:<br> Question below
ozzi

Answer:

b) 2.0 mol

Explanation:

Given data:

Number of moles of Ca needed = ?

Number of moles of water present = 4.0 mol

Solution:

Chemical equation:

Ca + 2H₂O     →      Ca(OH)₂ + H₂

now we will compare the moles of Ca and H₂O .

                          H₂O        :        Ca                

                             2           :        1

                             4.0           :       1/2×4.0 = 2.0 mol

Thus, 2 moles of Ca are needed.      

         

3 0
3 years ago
This question has multiple parts. Work all the parts to get the most points. An aqueous antifreeze solution is 39.0% ethylene gl
nlexa [21]

Answer:

Molality = <u>10.300 m</u>

<u>Molarity = 6.5970 M</u>

<u>mole fraction = </u>0.156549

Explanation:

39.0 % = ethylene glycol

61.0 % = water

imagine the total mass = 100g

39.0% ethylene glycol = 39g

61.0 % water = 61g

1) Molality = number of moles / mass of solvent (kg)

Molar mass of ethylene glycol = 62.07g/mole

mole = 39g / 62.07g/mole = 0.6283 moles

Molality = moles / mass of solvent = 0.6283 moles / 0.061kg = <u>10.300 m</u>

<u />

<u>2) Molarity</u> = number of moles / volume of solution

Since we know the density  of the solution = 1.05g /ml

⇒ volume = 100g / 1.05g /mL   = 95.24 mL = 0.09524 L

Molarity = 0.6283 moles / 0.09524 L = <u>6.5970 M</u>

3) Mole fraction

moles water = 61g / 18.02g/mole  = 3.38513 moles

Total number of moles = moles of ethylene glycol + moles of water = 0.6283 + 3.38513 = 4.0134276 moles

Mole fraction = 0.6283/ 4.0134276 = 0.156549

3 0
3 years ago
What type of energy is present in a barbell being lifted or a shot-put being thrown?
denpristay [2]
The type of energy used is kinetic energy. Kinetic energy is the energy of motion. 
8 0
3 years ago
Read 2 more answers
Calculate the molarity of a solution that contains 4.7 moles in 5.2 liters.
AleksAgata [21]

Answer:

0.9M

Explanation:

molarity = mols/L

M=4.7mol/5.2L

= 0.9M

4 0
3 years ago
I have trouble figuring out these questions help!!
Zina [86]
1. Density=mass/volume=2kg/6m=0.33kg/m (convert to proper units)
2. Density=mass/volume=0.6kg/3L=0.2kg/L (convert to proper units) 
3. Density=mass/volume= 129g / 30 cm (convert to proper units)
V=length*width*height=2*3*5 = 30
4. Volume (units) = cm^3 because, like in problem 3, Volume=width(cm)*length(cm)*height(cm)
However, when you pour liquid into a cylinder (so the volume would be the liquid), you measure it in mL.
5. Volume with rock - initial volume (without the rock) = Volume of rock
18.2-12.7= 5.5
3 0
3 years ago
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