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melomori [17]
3 years ago
11

For a hydrogen-like atom, classify these electron transitions by whether they result in the absorption or emission of light.

Chemistry
2 answers:
Nataly_w [17]3 years ago
7 0

Explanation:

When an electron absorbs the light it jumps from its lower energy state  towards the higher energy state. This known as absorption.

When an electron come backs from higher energy to lower energy level energy is released emitted out in the form of light. This is known as emission.

1) n = 3 to n = 5 ,This transition will be absorption.

2) n = 1 to n = 3 ,This transition will be absorption

3) n = 3 to n = 2 ,This transition will be emission.

4) n = 2 to n = 1 ,This transition will be emission.

zepelin [54]3 years ago
7 0

The transition from n = 3 to n = 5 energy level is an \boxed{{\text{absorption process}}}.

The transition from n = 1 to n = 3 energy level is an\boxed{{\text{absorption process}}}.

The transition from n = 3 to n = 2 energy level is an\boxed{{\text{emission process}}}.

The transition from n = 2 to n = 1 energy level is an\boxed{{\text{emission process}}}.

Further explanation:

An electronic transition is a process that occurs when an electron undergoes emission or absorption from one energy level to another energy level.

When an electron undergoes a transition from a lower energy level to a higher energy level then it requires energy to complete the process. This transition is an absorption process.

When an electron undergoes a transition from higher energy level to lower energy level then it emits energy to complete the process. This transition is an emission process.

The hydrogen atoms are dissociated when an electric discharge is passed through its molecules. As a result, electromagnetic radiations are emitted by the excitation of hydrogen atoms. The hydrogen spectrum contains radiations of different frequencies.

The formula to calculate the energy of transition in the hydrogen atom is as follows:

\boxed{\Delta E = {R_{\text{H}}}\left( {\frac{1}{{{{\left( {{{\text{n}}_{\text{i}}}} \right)}^2}}} - \frac{1}{{{{\left( {{{\text{n}}_{\text{f}}}} \right)}^2}}}} \right)}

Here,

\lambda is the wavelength of transition.

{R_{\text{H}}}is Rydberg constant.

{{\text{n}}_{\text{1}}}is the initial energy level of transition.

{{\text{n}}_{\text{2}}}is the final energy level of transition.

When the transition occurs from the first energy level to any other level, it is termed as Lyman series.

When the transition occurs from the second energy level to any other level, it is termed as Balmer series.

When the transition occurs from the third energy level to any other level, it is termed as Paschen series.

When the transition occurs from the fourth energy level to any other level, it is termed as Brackett series.

When the transition occurs from the fifth energy level to any other level, it is termed as Pfund series.

n = 3 to n = 5

Here, the electron goes from the lower energy level (n = 3) to a higher energy level (n = 5), so energy is absorbed in this process. Hence, this transition is classified as an absorption process.

n =1 to n = 3

Here, the electron goes from the lower energy level (n = 1) to a higher energy level (n = 3), so energy is absorbed in this process. Hence, this transition is classified as an absorption process.

n = 3 to n = 2

Here, the electron goes from higher energy level (n = 3) to lower energy level (n = 2), therefore energy is emitted in this process. Hence, this transition is classified as an emission process.

n = 2 to n = 1

Here, the electron goes from higher energy level (n = 2) to lower energy level (n = 1), therefore energy is emitted in this process. Hence, this transition is classified as an emission process.

Learn more:

1. Which transition is associated with the greatest energy change? brainly.com/question/1594022

2. Describe the spectrum of elemental hydrogen gas: brainly.com/question/6255073

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: hydrogen spectrum, Lyman, Balmer, Paschen, Brackett, Pfund, RH, ni, nf, first, second, third, fourth, fifth, emission, absorption.

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Coefficients are used in a chemical formula to show the number of each element. True or False
ANTONII [103]

Answer:

The same number of each element present before the reaction takes place must also be present on the product side of the equation. Coefficients are placed in front of a chemical formula to show the number of moles of that substances that are necessary for the reaction to occur.

Explanation:

5 0
2 years ago
The pH of a solution is 8. Some hydrochloric acid is added to the solution. Suggest the pH of the solution after mixing. pH=....
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Answer:

Probably around 6 because the ph of hydrochloric acid is 3

Explanation:

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2 years ago
In the world of chemistry, a 'mole' is a number of something... a very large number of something.
kipiarov [429]

Given:

No of atoms present= 8.022 x 10^23 atoms

Now we know that 1 mole= 6.022 x 10^23 atoms


Hence number of moles present in 8.022 x 10^23 atoms is calculated as below.

Number of moles

= 8.022 x 10^23/6.022x 10^23

=1.3 moles.

Hence we have 1.3 moles present.

3 0
2 years ago
The atom with the same number of neutrons as 12C is 9Be. 11B. 13C. 14N.
julia-pushkina [17]

Answer : The atom with the same number of neutrons as ^{12}C is, ^{11}B

Explanation :

  • The given atom is, ^{12}C

Atomic mass number = 12

Atomic number = 6

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass number - Atomic number = 12 - 6 = 6

Now we have to determine the number of neutrons in the given options.

  • In atom, ^{9}Be

Atomic mass number = 9

Atomic number = 4

Atomic number = Number of protons = Number of electrons = 4

Number of neutrons = Atomic mass number - Atomic number = 9 - 4 = 5

  • In atom, ^{11}B

Atomic mass number = 11

Atomic number = 5

Atomic number = Number of protons = Number of electrons = 5

Number of neutrons = Atomic mass number - Atomic number = 11 - 5 = 6

  • In atom, ^{13}C

Atomic mass number = 13

Atomic number = 6

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass number - Atomic number = 13 - 6 = 7

  • In atom, ^{14}N

Atomic mass number = 14

Atomic number = 7

Atomic number = Number of protons = Number of electrons = 7

Number of neutrons = Atomic mass number - Atomic number = 14 - 7 = 7

Therefore, the atom with the same number of neutrons as ^{12}C is, ^{11}B

6 0
3 years ago
A hypothetical element consists of two isotopes of masses 86.95amu and 88.95amu with abundances of 35.5% and 64.5% respectively.
Art [367]

Answer: The average atomic mass of the element = 88.242amu

Explanation:

The abundance of the first isotope is =35.5%

 Atomic mass of first isotope = 68.9257

The average atomic mass of the first isotope =86.95amu X 35.5%  =86.95amu X 0.355 =30.8725 amu

The abundance of the second isotope =64.5%

Atomic mass of the second isotope =88.95amu

The average atomic mass of second isotope =88.95amu x 64.5% = 88.95amu x 0.645= 57.37275 amu

Now the average atomic mass =30.8725 +57.37275 = 88.242amu

OR using the formulae

Average atomic mass = [mass of isotope× its abundance] + [mass of isotope× its abundance] +...[ ] / 100

{(86.95amu X 35.5 )+(88.95amu x 64.5)}/100

8,824/100

=88.24amu

5 0
2 years ago
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