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melomori [17]
4 years ago
11

For a hydrogen-like atom, classify these electron transitions by whether they result in the absorption or emission of light.

Chemistry
2 answers:
Nataly_w [17]4 years ago
7 0

Explanation:

When an electron absorbs the light it jumps from its lower energy state  towards the higher energy state. This known as absorption.

When an electron come backs from higher energy to lower energy level energy is released emitted out in the form of light. This is known as emission.

1) n = 3 to n = 5 ,This transition will be absorption.

2) n = 1 to n = 3 ,This transition will be absorption

3) n = 3 to n = 2 ,This transition will be emission.

4) n = 2 to n = 1 ,This transition will be emission.

zepelin [54]4 years ago
7 0

The transition from n = 3 to n = 5 energy level is an \boxed{{\text{absorption process}}}.

The transition from n = 1 to n = 3 energy level is an\boxed{{\text{absorption process}}}.

The transition from n = 3 to n = 2 energy level is an\boxed{{\text{emission process}}}.

The transition from n = 2 to n = 1 energy level is an\boxed{{\text{emission process}}}.

Further explanation:

An electronic transition is a process that occurs when an electron undergoes emission or absorption from one energy level to another energy level.

When an electron undergoes a transition from a lower energy level to a higher energy level then it requires energy to complete the process. This transition is an absorption process.

When an electron undergoes a transition from higher energy level to lower energy level then it emits energy to complete the process. This transition is an emission process.

The hydrogen atoms are dissociated when an electric discharge is passed through its molecules. As a result, electromagnetic radiations are emitted by the excitation of hydrogen atoms. The hydrogen spectrum contains radiations of different frequencies.

The formula to calculate the energy of transition in the hydrogen atom is as follows:

\boxed{\Delta E = {R_{\text{H}}}\left( {\frac{1}{{{{\left( {{{\text{n}}_{\text{i}}}} \right)}^2}}} - \frac{1}{{{{\left( {{{\text{n}}_{\text{f}}}} \right)}^2}}}} \right)}

Here,

\lambda is the wavelength of transition.

{R_{\text{H}}}is Rydberg constant.

{{\text{n}}_{\text{1}}}is the initial energy level of transition.

{{\text{n}}_{\text{2}}}is the final energy level of transition.

When the transition occurs from the first energy level to any other level, it is termed as Lyman series.

When the transition occurs from the second energy level to any other level, it is termed as Balmer series.

When the transition occurs from the third energy level to any other level, it is termed as Paschen series.

When the transition occurs from the fourth energy level to any other level, it is termed as Brackett series.

When the transition occurs from the fifth energy level to any other level, it is termed as Pfund series.

n = 3 to n = 5

Here, the electron goes from the lower energy level (n = 3) to a higher energy level (n = 5), so energy is absorbed in this process. Hence, this transition is classified as an absorption process.

n =1 to n = 3

Here, the electron goes from the lower energy level (n = 1) to a higher energy level (n = 3), so energy is absorbed in this process. Hence, this transition is classified as an absorption process.

n = 3 to n = 2

Here, the electron goes from higher energy level (n = 3) to lower energy level (n = 2), therefore energy is emitted in this process. Hence, this transition is classified as an emission process.

n = 2 to n = 1

Here, the electron goes from higher energy level (n = 2) to lower energy level (n = 1), therefore energy is emitted in this process. Hence, this transition is classified as an emission process.

Learn more:

1. Which transition is associated with the greatest energy change? brainly.com/question/1594022

2. Describe the spectrum of elemental hydrogen gas: brainly.com/question/6255073

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: hydrogen spectrum, Lyman, Balmer, Paschen, Brackett, Pfund, RH, ni, nf, first, second, third, fourth, fifth, emission, absorption.

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Solution:
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                                           K  +  O₂     →     KO₂

First let us confirm that either the given amount of Potassium produces the given amount of Potassium oxide or not,
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As,
                39.098 g (1 mole) K produced  =  71.098 g of K₂O
So,
                          3.91 g of K will produce  =  X g of K₂O

Solving for X,
                      X  =  (3.91 g × 71.098 g) ÷ 39.098

                      X  =  7.11 g of K₂O

Hence, it is confirmed that we have selected the right equation,
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As,
                     39.098 g of K required  =  32 g of O₂
So,
                     3.91 g of K will require  =  X g of O₂

Solving for X,
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