Answer : The maximum amount of nickel(II) cyanide is 
Explanation :
The solubility equilibrium reaction will be:

Initial conc. 0.220 0
At eqm. (0.220+s) 2s
The expression for solubility constant for this reaction will be,
![K_{sp}=[Ni^{2+}][CN^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BNi%5E%7B2%2B%7D%5D%5BCN%5E-%5D%5E2)
Now put all the given values in this expression, we get:


Therefore, the maximum amount of nickel(II) cyanide is 
4.1g
Explanation:
Given parameters:
Mass of carbon dioxide = 15g
Mass of oxygen gas = 11g
Unknown:
Mass of carbon consumed = ?
Solution:
Equation of the reaction:
C + O₂ → CO₂
To solve this problem from the balanced equation, we have to use the amount of product formed and work to Carbon. This is because, we are sure of the amount of carbon dioxide formed but the amount of the given oxygen gas used is not precise.
Number of moles of CO₂ = 
Molar mass of CO₂ = 12 + (16 x2) = 44g/mol
Number of moles of CO₂ =
= 0.34mole
From the equation of the reaction;
1 mole of CO₂ is produced from 1 mole of C
0.34mole of CO₂ will produce 0.34mole of C
Mass of carbon reacting = number of moles x molar mass = 0.34 x 12 = 4.1g
Learn more:
Number of moles brainly.com/question/1841136
#learnwithBrainly
Answer:
Step 1;
q = w = -0.52571 kJ, ΔS = 0.876 J/K
Step 2
q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ
Explanation:
The given parameters are;
= 100 N·m
= 327 K
= 90 N·m
Step 1
For isothermal expansion, we have;
ΔU = ΔH = 0
w = n·R·T·ln(
/
) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71
w ≈<em> -0.52571</em> kJ
At state 1, q = w = -0.52571 kJ
ΔS = -n·R·ln(
/
) = -1 × 8.314 × ln(90/100) ≈ 0.876
ΔS ≈ 0.876 J/K
Step 2
q = 0 for adiabatic process
ΔU = 25×(27 - 327) = -7,500
w = ΔU = <em>-7.5 kJ</em>
ΔH = ΔU + n·R·ΔT
ΔH = -7,500 + 8.3142 × 300 = -5,005.74
ΔH = ΔU = <em>-5.00574 kJ</em>
Here you are! I hope it helps, and also for the ones I put a red ‘x’ it depends on how you round it.
Solute and solvent form a solution, which means two different kinds of molecules/atoms/compounds are mixed together, therefore, it is a mixture.