Answer:
R=4Ω
Explanation:
R1 and R3 are parrallel
so we have : R=R1*R2/R1+R2
R=6*3/6+3
R=18/9
R=2Ω
R2 and 2Ω are in series,so we have
R=R2+2
R=2+2
R=4Ω
Answer:
The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.
Explanation:
Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.
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Answer:
Force, F = 500 N
Explanation:
Given that,
Power expanded, P = 1000 W
Distance moved by piano, d = 10 m
Time taken, t = 5 s
To find,
The force exerted by the person
Solution,
The rate at which the work is being done is called power delivered. Its formula is given by:
W is the work done, W = F × d
On rearranging the above formula to find F as :
F = 500 N
Therefore, the force exerted on the person is 500 N. Hence, this is the required solution.
