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2 years ago

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The thrust F of a screw propeller is known to depend upon the diameter d, Speed of advance v, fluid density e, revolution per se

cond N, and the coefficient of viscosity M, of the fluid. Find the expression for F, in terms of the quantities

1 answer:

Dafna1 [17]2 years ago

3 0

Answer:

${ \bf{F = { \tt{ \frac{4}{3} \pi {r}^{3}v gM}}}}$

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Driving on asphalt roads entails very little rolling resistance, so most of the energy of the engine goes to overcoming air resi

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Answer:

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Explanation:

a) Let assume that car travel on a horizontal surface. The equations of equilibrium of the car are:

$\Sigma F_{x} = F - \mu_{r}\cdot N = 0$

$\Sigma F_{y} = N - m\cdot g = 0$

After some algebraic handling, the following expression for the propulsion force is constructed:

$F = \mu_{r}\cdot m \cdot g$

$F = (0.06)\cdot (1500\,kg)\cdot (9.807\,\frac{m}{s^{2}} )$

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b) The power require to move the car at a speed of 5 meters per second is:

$\dot W = F\cdot v$

$\dot W = (882.63\,N)\cdot (5\,\frac{m}{s} )$

$\dot W= 4413.15\,W$

c) The efficiency of the car is:

$\eta = \frac{(882.63\,N)\cdot (15\,mi)\cdot (\frac{1609\,m}{1\,mi} )}{(1.4\times 10^{8}\,J)} \times 100\,\%$

$\eta = 15.216\,\%$

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