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gizmo_the_mogwai [7]
4 years ago
15

An electric current heats a 221 g (0.221 kg) copper wire from 20.0 °C to 38.0 °C. How much heat was generated by the current?

(Ccopper = 0.093 kcal/kgC°)
Physics
1 answer:
lorasvet [3.4K]4 years ago
3 0

Answer:

Heat generated by the current = 1547.89 J

Explanation:

We have equation for heat energy H = mCΔT

Mass of copper = 0.221 kg

Specific heat of copper = 0.093 kcal/kgC° = 389.112 J/kgC°

ΔT = 38 - 20 = 18°C

Substituting in H = mCΔT

           H = 0.221 x 389.112 x 18 = 1547.89 J

Heat generated by the current = 1547.89 J

     

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An output gear has 10 teeth and an input gear has 40 teeth. What is the mechanical advantage of gear combination? Is force or sp
yKpoI14uk [10]

Answer:

Mechanical advantage: 4. Speed is multiplied

Explanation:

The mechanical advantage of gear combination is

MA = \frac{N_i}{N_o}

where

N_i is the number of teeth in the input gear

N_o is the number of teeth in the output gear

Here we have

N_i = 40\\N_o = 10

So we find

MA = \frac{40}{10}=4

In this example, it is the speed to be multiplied: the speed of the output gear is 4 times larger than the speed of the input gear. In fact, the mechanical advantage can be rewritten as

MA= \frac{\omega_o}{\omega_i}

where

\omega_i is the angular speed of the input gear

\omega_o is angular speed of the output gear

So re-arranging the equation, we find

\omega_o = MA \cdot \omega_i = 4 \omega_i

so, the speed of the output gear is 4 times larger than the speed of the input gear.

7 0
3 years ago
A helicopter’s velocity increases from 35 m/s to 70 m/s in 10 seconds. What is the acceleration of this helicopter?
Alenkinab [10]
3.5 meters per second second is the acceleration because we know that acceleration is change in velocity over time and the change is velocity here is 35 and the time is 10 so we can simply divide 35 by 10 which is 3.5 m/s squared
3 0
3 years ago
A car accelerates for 10 seconds. During this time, the angular
bagirrra123 [75]

Answer:

the angular acceleration of the car is 1.5 rad/s²

Explanation:

Given;

initial angular velocity, \omega_i = 10 rad/s

final angular velocity, \omega_f = 25 rad/s

time of motion, t = 10 s

The angular acceleration of the car is calculated as follows;

a_r = \frac{\omega_f - \omega_i }{t} \\\\a_r = \frac{25-10}{10} = 1.5 \ rad/s^2

Therefore, the angular acceleration of the car is 1.5 rad/s²

4 0
3 years ago
Am i right on this one?
NISA [10]

well if each square is 6 km, then the car DOES go 6 km, but it also moves WEST, not east. i would say that since its displacement not distance, its 2 km WEST :)

4 0
3 years ago
Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a co
Igoryamba

Answer:

a. before

Explanation:

Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a constant 1 mm?

from the graph given from a source. the vertical axis represents the displacement of the graph motion, whilst the horizontal side is representing the time variable of the motion .

displacement is distance in a specific direction.

before the displacement was maximum at 2mm was instant at time=0.04s.

But later was constant at 0.06s at a displacement point of 1mm

4 0
4 years ago
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