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svet-max [94.6K]
3 years ago
13

A standard 1 kilogram weight is a cylinder 49.5 mm in height and 52.5 mm in diameter. What is the density of the material? kg/m3

Physics
1 answer:
sergij07 [2.7K]3 years ago
8 0

Answer:

91659.02kg/m^3

Explanation:

We have given mass m = 1 kg

Height of the cylinder h=49.5mm=49.5\times 10^(-3)m

Diameter d=52.5 mm , so radius r=\frac{d}{2}=\frac{52.5}{2}=26.25mm=26.25\times 10^{-3}m

Volume of the cylinder V=\pi r^2h=3.14\times (26.25\times 10^{-3})^2\times 49.5\times 10^{-3}=1.091\times 10^{-5}m^3

We know that density d=\frac{mass}{volume}=\frac{1}{1.091\times 10^{-5}}=91659.02kg/m^3

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Answer:

Option B. N2(g) + 3H2(g) → 2NH3(g)

Explanation:

When nitrogen react with hydrogen, they form a product as shown below:

N2+ H2 → NH3

We need to balance the equation. This is illustrated below:

There are 2 atoms of nitrogen on the left side and 1 atom on the right side. To balance it, put 2 in front of NH3 as shown below:

N2+ H2 → 2NH3

Now, There are a total of 6 atoms of Hydrogen on the right side and 2 atoms on the left side side. This can be balanced by putting 3 in front of H2 as shown below:

N2+ 3H2 → 2NH3

Now we see clearly that the equation is balanced as we have equal numbers of atoms of N and H on both sides of the equation

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13. Describe the molecules of a solid in terms of kinetic energy.
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Blocks A and B of unknown masses m1 and m2, respectively, are set up on an inclined plane as shown. Block A is attached to block
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Newton's second law we can find that the correct answer is:  

 E)  It cannot be determiner whick block has more masses from the information provided

Newton's second law establishes the relationship between force, mass, and acceleration of a body. Since force and acceleration are vector quantities, their components must be added on each axis

For this problem we have two bodies, let's write Newton's second law for the body B, we assume that the body B descends

            W_b - T = m_b a

            W_b  = m_b g

            m_b - T = m_b a

Where W_b is the weight of block B, T the tension of the string, mb the mass of block b and the acceleration

Now let's find the relation for block A

let's set a datum with the x axis parallel to the ramp

           T - Wₓ = mₐ a

           sin θ = Wₓ / W

            Wₓ = Wₐ sin θ

             Wₐ = mₐ g

Where Wₓ is the component of the weight, Wₐ the weight of the body A and θ the angle of the plane

Let's write our system of equations

           m_b g - T = m_b a

           T - mₐ g sin θ = mₐ a

let's add the equations

            g (m_b - mₐ sin θ) = (m_b + mₐ) a

            a =   \frac{m_b - m_a \ sin  \ \theta}{m_b+m_a} \ g

Let's analyze this expression

  • The numerator is positive the body B descends, this occurs when

          m_b - mₐ sin θ > 0

           

  • The numerator is negative, body B rises

           m_b - mₐ  sin θ <0

We can observe that the acceleration is positive or negative depending on the relation of the masses and the angle of the plane.

In conclusion using Newton's second law we find that the correct answer is  

 E )   It cannot be determiner whick block has more masses from the information provided

learn more about Newton's second law here:

brainly.com/question/9099891

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