Answer:
-54 m/s²
Explanation:
Acceleration is defined as the change in velocity of a body with respect to time. Mathematically,
Acceleration A = change in velocity/time
A = dv/dt
Given Vx = at − bt³
The time at which the particle reaches its maximum displacement is at when vx = 0.
0 = at-bt³
t(a-bt²) = 0
a-bt² = 0
a = bt²
t² = a/b ... (1)
A = dvx/dt = a - 3bt²(by differentiating)
Acceleration = a - 3bt²... (2)
Substituting t² = a/b into equation 2 will give;
Acceleration = a - 3b(a/b)
Acceleration = a-3a
Acceleration = -2a
Substituting the value of a = 27m/s into the resulting equation of acceleration gives;
Acceleration = -2(27)
Acceleration = -54m/s²
Therefore at maximum displacement in the positive x direction, the acceleration of the particle will be -54m/s²
I believe the answer is b. external stimulus
A. The elections neartest to tye nuclear
