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Dimas [21]
3 years ago
11

When someone standing at one end of a large room opens a bottle of vinegar, it may take several minutes for a person at the othe

r end to smell it. gas molecules at room temperature move at very high velocities, so what is responsible for the delay in detection of the vinegar?
Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Out of the following given choice:

A.  The increase in the airspace occupied by vinegar molecules

B. The chemical reaction with nerves, which is slower than other sensory processes

C. Attractive forces between the air and vinegar molecules

D. Random collisions between the air and vinegar molecules.

<span>The answer is D. While the particles may be moving at high velocities even at room temperatures, the delay is due to the numerous collisions between the vinegar molecules and the air molecules.This changes the vinegar’s molecules directions from straight lines to random unpredictable paths</span>




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Divergent plate boundary

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Calculate the number of liters in 3.25 g of ammonia
il63 [147K]

 The liters in   3.25 g   of  ammonia  4.28 L


  <u><em>calculation</em></u>

 Step 1: find moles of ammonia

 moles = mass÷ molar  mass

 From  periodic    table  the molar mass  of ammonia (NH₃)  =  14 +(1×3 ) = 17  g/mol

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Step 2: find the number of liters of ammonia

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8 0
3 years ago
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Calculate the total energy, in kilojoules, that is needed to turn a 46 g block
neonofarm [45]

Answer: The total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

Explanation:

Given: Mass = 46 g

Initial temperature = -25^{o}C

Final temperature = 100^{o}C

Specific heat capacity of ice = 2.05 J/g^{o}C

Formula used to calculate the energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 46 g \times 2.05 J/g^{o}C \times (100 - (-25))^{o}C\\= 11787.5 J (1 J = 0.001 kJ)\\= 11.787 kJ

Thus, we can conclude that the total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

7 0
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