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Dimas [21]
3 years ago
11

When someone standing at one end of a large room opens a bottle of vinegar, it may take several minutes for a person at the othe

r end to smell it. gas molecules at room temperature move at very high velocities, so what is responsible for the delay in detection of the vinegar?
Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Out of the following given choice:

A.  The increase in the airspace occupied by vinegar molecules

B. The chemical reaction with nerves, which is slower than other sensory processes

C. Attractive forces between the air and vinegar molecules

D. Random collisions between the air and vinegar molecules.

<span>The answer is D. While the particles may be moving at high velocities even at room temperatures, the delay is due to the numerous collisions between the vinegar molecules and the air molecules.This changes the vinegar’s molecules directions from straight lines to random unpredictable paths</span>




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When dissolved in water, a neutral molecule of calcium chloride dissociates into three ions - one calcium ion and two chloride i
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Explanation:

Calcium chloride is an ionic compound as it is formed by transfer of an electron to each chlorine atom.

So, being an ionic compound calcium chloride is able to dissociate completely into water.

Hence, the dissociation reaction will be as follows.

         CaCl_{2}(s) \rightarrow Ca^{2+}(aq) + 2Cl^{-}(aq)

Since, two electrons has been lost by single calcium atom. Therefore, calcium atom will have a charge of +2.

Thus, we can conclude that the charge on the calcium ion, in elementary units is +2.

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II. Practice An ideal gas occupies 5 L at atmospheric pressure and 300 K (point A). It is warmed at constant volume to 3 atm (po
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Answer:

The process can be represented as shown in the figure below; having got the diagram, we can solve for the questions.

A. the number of moles of gas used

n = PV/ RT = (1.013 *10^5 Pa) * (5.0 *10^-3 m^3) / (8.314 * 300)

n =  5.065 * 10^2 / 2494.2

n = 0.00203 *10^2

n = 0.203 moles

B. Temperature at point C (Tc)

Pa/Ta= Pb/Tb

Tb = Pb *Ta / Pa

Tb = 3 * 300 / 1

Tb = 900 K

Since Tb = Tc = 900 K

C. For process AB,

work done is zero

For process BC,

work done = -nRTbln (Vc/Vb)

W = -(0.203 * 8.314 * 900 ln (3)  

W = -(1.518 kJ ln 3

W = -1.67 kJ

For process CA,

W = -P V =-nRT

W = -(0.203 * 8.314 * (-600))

W = 1.01 kJ

Explanation:

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4 years ago
What part is labeled a
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How am I supposed to know, your not even showing the part lol
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Answer:

1:Basic /2: acidic/ 3: neutral

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