Answer:
3.55atm
Explanation:
We will apply Boyle's law formula in solving this problem.
P1V1 = P2V2
And with values given in the question
P1=initial pressure of gas = 1.75atm
V1=initial volume of gas =7.5L
P2=final pressure of gas inside new piston in atm
V2=final volume of gas = 3.7L
We need to find the final pressure
From the equation, P1V1 = P2V2,
We make P2 subject
P2 = (P1V1) / V2
P2 = (1.75×7.5)/3.7
P2=3.55atm
Therefore, the new pressure inside the piston is 3.55atm
Shielding effect being attendency of the inner electrons to repel the outermost electrons, an increase in shielding effect increases atomic radius and decrease reduces the atomic radius
Answer:
2.355atm
Explanation:
To get the pressure of helium, we need to get the mole fraction of helium.
The total mole fraction for any mixture of gases equals 1. Hence to get the mole fraction of the helium, we simply subtract the addition of the mole fractions of neon and argon from 1.
This means - 1 - 0.47 - 0.23 = 0.3
Now, to get the pressure of the helium gas, we simply multiply the total pressure by 0.3. This is 0.3 * 7.85 = 2.355 atm
Answer:
224 grams of O₂
Explanation:
This is the reaction:
2 C₂H₆ (g) + 7 O₂(g) → 4 CO₂ (g) + 6 H₂O (g)
2 moles of ethene react with 7 moles of oxygen.
Let's convert the ethene's mass into moles (mass / molar mass)
60 g / 30 g/m = 2 mol
So, if 2 moles of ethene must react with 7 moles of O₂ and we have 2 moles, obviously we would need 7 moles of oyxgen.
Let's convert the moles to mass ( mol . molar mass)
7 m . 32 g/m = 224 grams
