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2 years ago

The sturdy wall outside of a skyscraper could be most easily compared to

1 answer:

3 0

I think the answer is A because the job of a cell membrane is to provide protection to the plant. A cell membrane has a sturdy wall.

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5) Determine the mass if lithium hydroxide that is produced when 12.87 g of lithium

netineya [11]

Answer: 26.54 grams

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of lithium nitride}=\frac{12.87g}{34.83g/mol}=0.369moles$

$Li_3N+3H_2O\rightarrow 3LiOH+NH_3$

$Li_3N$ is the limiting reagent as it limits the formation of product and $H_2O$ is the excess reagent

According to stoichiometry :

As 1 moles of $Li_3N$ give = 3 moles of $LiOH$

Thus 0.369 moles of $O_2$ give = $\frac{3}{1}\times 0.369=1.108moles$ of $LiOH$

Mass of $LiOH=moles\times {\text {Molar mass}}=1.108moles\times 23.95g/mol=26.54g$

Thus 26.54 g of $LiOH$ will be produced from the given mass.

4 0

3 years ago

Separation of mixtures and purification of chemical substances

Mnenie [13.5K]

Answer:

I don't understand what to do with this

4 0

2 years ago

All of the following are features of karst topography EXCEPT sinkholes. Disappearing and emerging streams. Caverns. Continuous s

Minchanka [31]

D, continuous streams.

4 0

2 years ago

Which statement describes the phase change that occurs when dry ice is placed in an open container at room temperature?

zloy xaker [14]

Answer:

Dry ice undergoes sublimation, an endothermic change at room temperature.

7 0

3 years ago

Read 2 more answers

An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 113 amu and 115 amu, with natural abunda

DENIUS [597]

Answer: Its average atomic mass is 114.9 amu

Explanation:

Mass of isotope 1 = 113 amu

% abundance of isotope 1 = 5% = $\frac{5}{100}=0.05$

Mass of isotope 2 = 115 amu

% abundance of isotope 2 = 95% = $\frac{95}{100}=0.95$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(113\times 0.05)+(115\times 0.95)]$

$A=114.9amu$

Thus its average atomic mass is 114.9 amu

5 0

2 years ago