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Zigmanuir [339]
3 years ago
14

The phospholipid molecule has two parts, the polar end and the bipolar end. True or false

Physics
1 answer:
inessss [21]3 years ago
4 0
The above statement is FALSE.

The Phospholipid molecule has two parts, the polar end and the NONPOLAR end.

The polar region of a phospholipid contains: glycerol, carbonyl O of fatty acids, Pi, & the polar head group (X)

The non-polar region of a phospholipid conatins: hydrocarbon tails of fatty acids (R1, R2). 
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Gravitational energy can be negative?
AlladinOne [14]

answer:

yes

explanation:

At a separation of the surface of Earth (r=6400km) gravity wants pull the test mass closer and closer. ... So the work done by gravity is NEGATIVE. The gravitational potential energy is negative because us trying to do the opposite of what gravity wants needs positive energy.

6 0
3 years ago
What three things can happen to water when it falls on earth's surface
777dan777 [17]
It can be stored on the land surface as ice and snow...it can seep into the earth and be stored as surface water...it can flow in the surface of lands.
3 0
3 years ago
What is the proper battery cable connection when jumping two automotive batteries? (a) negative to negative / positive to positi
Vladimir [108]
<span>The proper </span><span>battery cable connection when jumping two automotive batteries is :  </span><span>(a) negative to negative / positive to positive. 

</span><span>Connect the red (positive) cable from the car with the bad battery to the red (positive) on the good battery. </span>

<span>Then connect the black (negative) from the good battery to a grounding point on the other car which should be tightened and metal should be clean.
</span>
<span>Once the car with bad battery has started, the removal of the cable should be in the opposite order. The Red (positive) which was the the First Cable to go on should be the last cable to be taken off.</span>


3 0
3 years ago
A circular radar antenna on a Coast Guard ship has a diameter of 2.10 m and radiates at a frequency of 16.0 GHz. Two small boats
Anna35 [415]

Answer:

d = 76.5 m

Explanation:

To find the distance at which the boats will be detected as two objects, we need to use the following equation:

\theta = \frac{1.22 \lambda}{D} = \frac{d}{L}

<u>Where:</u>

θ: is the angle of resolution of a circular aperture

λ: is the wavelength

D: is the diameter of the antenna = 2.10 m

d: is the separation of the two boats = ?

L: is the distance of the two boats from the ship = 7.00 km = 7000 m

To find λ we can use the following equation:

\lambda = \frac{c}{f}

<u>Where:</u>

c: is the speed of light = 3.00x10⁸ m/s

f: is the frequency = 16.0 GHz = 16.0x10⁹ Hz

\lambda = \frac{c}{f} = \frac{3.00 \cdot 10^{8} m/s}{16.0 \cdot 10^{9} s^{-1}} = 0.0188 m            

Hence, the distance is:

d = \frac{1.22 \lambda L}{D} = \frac{1.22*0.0188 m*7000 m}{2.10 m} = 76.5 m

Therefore, the boats could be at 76.5 m close together to be detected as two objects.

 

I hope it helps you!

7 0
3 years ago
In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 200 WW electric im
ivolga24 [154]

Answer:

The heat is 115478.4 J.

Explanation:

Given that,

Mass of water = 0.400 kg

Power = 200 W

Suppose, we determine how much heat must be added to the water to raise its temperature from 20.0°C to 89.0°C?

We need to calculate the heat

Using formula of heat

Q=mc\Delta T

Where, m = mass of water

c = specific heat

Put the value into the formula

Q=400\times4.184\times(89-20)

Q=115478.4\ J

Hence, The heat is 115478.4 J.

7 0
3 years ago
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