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pantera1 [17]
3 years ago
7

A person wants to make a metronome for music practice. He uses a 35-g object attached to a spring to serve as the time standard.

Physics
1 answer:
alukav5142 [94]3 years ago
7 0

To develop this problem it will be necessary to apply the concepts related to the frequency of a spring mass system, for which it is necessary that its mathematical function is described as

f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}

Here,

k = Spring constant

m = Mass

Our values are given as,

m = 35g = 35*10^{-3}kg

f = 1 Hz

Rearranging to find the spring constant we have that,

k = (2\pi f \sqrt{m})^2

k = 4\pi^2 f^2 m

k = (4) (\pi)^2 (1) (35*10^{-3})

k = 1.38N/m

Therefore the spring constant is 1.38N/m

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Explanation:

From the question we are told that

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