<h2>Ratio of free fall acceleration of Tokyo to Cambridge = 0.998</h2>
Explanation:
We know the equation
where l is length of pendulum, g is acceleration due to gravity and T is period.
Rearranging
Length of pendulum in Tokyo = 0.9923 m
Length of pendulum in Cambridge = 0.9941 m
Period of pendulum in Tokyo = Period of pendulum in Cambridge = 2s
We have
Ratio of free fall acceleration of Tokyo to Cambridge = 0.998
Answer:
A. 19.8 cm.
Explanation:
The apparent depth of the combination is
As it mentioned that the two clear but non-mixing liquid having depth of 15 cm that placed in a glass container together
Also the refractive indices would be 1.75 and 1.33
Based on the above information
As we know that
Refractive indices = real depth ÷ apparent depth
1.33 ÷ 1.75 = 15 ÷ apparent depth
So, it would be 19.736842 cm
Now the combination of apparent depth would be
= ( 19.736842 + 15) ÷ (1.75)
= 19.8 cm
hence, the correct option is A.
L = length of the meter stick = 1 m
h = height of center of mass of stick from bottom end on the floor = L/2 = 1/2 = 0.5 m
m = mass of the meter stick
I = moment of inertia of the meter stick about the bottom end
w = angular velocity as it hits the floor
moment of inertia of the meter stick about the bottom end is given as
I = m L²/3
using conservation of energy
rotational kinetic energy of meter stick as it hits the floor = potential energy when it is vertical
(0.5) I w² = m g h
(0.5) (m L²/3) w² = m g h
( L²) w² = 6g h
( 1²) w² = 6 (9.8) (0.5)
w = 5.4 rad/s
Answer:
The answer is
<h2>2560 J</h2>
Explanation:
The kinetic energy of an object given it's mass and velocity can be found by using the formula
where
m is the mass
v is the velocity
From the question
m = 80 kg
v = 8 m/s
The kinetic energy is
We have the final answer as
<h3>2560 J</h3>
Hope this helps you
Answer:
Explanation:
Given
launch velocity 
Launch angle 
Range of Projectile 
Horizontal velocity remain same and only vertical velocity changes.
Initially vertical velocity is in upward direction but as soon as it reaches the ground its direction change but magnitude remain same.
