Which option is an example of an object that has potential energy followed by an object that has kinetic energy?

1 answer:

6 0

A ball held over a person's head | a ball rolling on the floor is an example of an object that has potential energy followed by an object that has kinetic energy.

<h3>What is Kinetic energy?</h3>

This is the type of energy possessed by a body by virtue of its motion or movement.

The rolling ball therefore has kinetic energy while a ball being held over a person's head has potential energy which is the energy possessed by a body by virtue of its position.

Read more about Kinetic energy here brainly.com/question/8101588

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It takes 5.0 seconds for a wave with a wavelength of 2.5 m to travel past your location. What’s the period of the wave. What is

Anna35 [415]

(a) Period of the wave
The period of a wave is the time needed for a complete cycle of the wave to pass through a certain point.
So, if an entire cycle of the wave passes through the given location in 5.0 seconds, this means that the period is equal to 5.0 s: T=5.0 s.

(b) Frequency of the wave
The frequency of a wave is defined as
$f= \frac{1}{T}$
since in our problem the period is $T=5.0 s$ , the frequency is
$f= \frac{1}{5.0 s}=0.2 Hz$

(c) Speed of the wave
The speed of a wave is given by the following relationship between frequency f and wavelength $\lambda$ :
$v=f \lambda = (0.2 Hz)(2.5 m)=0.5 m/s$

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3 years ago

An object (initially at rest) is dropped from a height h above the ground if it takes 4 seconds for the object to reach the grou

seraphim [82]

Since U=0,
h=1/2gt^2 (h= ut+1/2gt^2, U=0)
h=1/2*10*4*4
h=80m

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2 years ago

The velocity of a 1.3 kg remote-controlled car is plotted on the graph. The work of segment A is J.

tamaranim1 [39]

Answer: 585 J

Explanation:

We can calculate the work done during segment A by using the work-energy theorem, which states that the work done is equal to the gain in kinetic energy of the object:

$W=K_f -K_i$

where Kf is the final kinetic energy and Ki the initial kinetic energy. The initial kinetic energy is zero (because the initial velocity is 0), while the final kinetic energy is

$K_f =\frac{1}{2}mv^2$