All categories

3 years ago

Why do these two magnets attract each other?

Physics

2 answers:

Ber [7]3 years ago

7 0

Answer:

A. The poles that face each other are opposite magnetic poles.

Liono4ka [1.6K]3 years ago

5 0

Answer:

Explanation:

When two magnets are brought near each other, like poles repel; opposite poles attract. We like to represent this force effect of a magnet on iron-like objects with a concept called magnetic field. The concept of field can be best understood if we remember the gravitational force of Earth on object near it.

You might be interested in

Please help: 2.Le pluriel Questions

sp2606 [1]

1. bleus

2. rouges

3. petites

4. actifs

5. gross

Just add an -s to make it plural

8 0

3 years ago

The temperature of the cosmic background radiation is measured to be 2.7 k. What is the wavelength of the peak in the spectral d

KATRIN_1 [288]

Answer:

$1.07\cdot 10^{-3} m$

Explanation:

The peak wavelength of the spectral distribution can be found by using Wien's displacement law:

$\lambda=\frac{b}{T}$

where

$b=2.898\cdot 10^{-3} m\cdot K$ is Wien's displacement constant

T is the absolute temperature

For the cosmic background radiation, the temperature is

T = 2.7 K

So, the corresponding peak wavelength is

$\lambda=\frac{2.898\cdot 10^{-3} m\cdot K}{2.7 K}=1.07\cdot 10^{-3} m$

7 0

3 years ago

Find the resistance of an electric light bulb if a current of 0.08 A flows when the potential difference across the bulb is 120

lora16 [44]

U=RI Ohm's law
then R=U/I
=120/0.08
=2250Ω
hope this helps you

8 0

3 years ago

The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 cm/s. Calculate the average speed

puteri [66]

Answer:

The average speed of the blood in the capillaries is 0.047 cm/s.

Explanation:

Given;

radius of the aorta, r₁ = 1 cm

speed of blood, v₁ = 30 cm/s

Area of the aorta, A₁ = πr₁² = π(1)² = 3.142 cm²

Area of the capillaries, A₂ = 2000 cm²

let the average speed of the blood in the capillaries = v₂

Apply continuity equation to determine the average speed of the blood in the capillaries.

A₁v₁ = A₂v₂

v₂ = (A₁v₁) / (A₂)

v₂ = (3.142 x 30) / (2000)

v₂ = 0.047 cm/s

Therefore, the average speed of the blood in the capillaries is 0.047 cm/s.

4 0

3 years ago

At the equator earth rotates with a velocity of about 465 m/s.

Dafna1 [17]

The given velocity is 465 m/s.

Part a.
$465 \, \frac{m}{s} =(465 \times 10^{-3} \, \frac{km}{s})*( 3600 \, \frac{s}{h} ) = 1674 \, \frac{km}{h}$
Answer: 1674 km/h

Part b.
$1674 \frac{km}{h} = (1674 \, \frac{km}{h})*(24 \, \frac{h}{day} ) = 40176 \, \frac{km}{day}$
Answer: 40,176 km/day.

3 0

3 years ago

Read 2 more answers