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Elis [28]
3 years ago
11

An atom of gold (Au) has 79 electrons. How many protons must it have if it has a net charge of 0?

Chemistry
2 answers:
Varvara68 [4.7K]3 years ago
6 0
In order to balance out the Electrons, and give it a net charge of 0, you would need 79 Protons.
RoseWind [281]3 years ago
5 0

Explanation:

It is known that for a neutral atom the number of protons present in that atom is equal to the number of electrons present in it.

Also, atomic number means the sum of total number of protons present in an atom.

For example, when a gold atom has net charge 0 then it means it is neutral in nature.

Also, it contains 79 electrons. This also means it contains 79 protons.

Thus, we can conclude that an atom of gold (Au) which has 79 electrons will also contain 79 protons.

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You multiply the number by 1000 when you convert a measurement from kilometres to metres.

The prefix <em>kilo</em> means <em>×1000</em>, so

1 <em>kilo</em>metre means 1 metre <em>×1000</em>.

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Solid strontium chromate, SrCrO4, dissolves into its respective ions at 25°C. Suppose that in a particular solution,
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Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

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