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aleksandrvk [35]
3 years ago
15

Two unlabelled bottles containing clear, colourless liquids are found in the organic section of the chemical storage room. Descr

ibe the chemical test that could be conducted in order to determine whether the two substances are unsaturated or saturated.
Chemistry
1 answer:
Paul [167]3 years ago
6 0
<span>The very first step you should do is to bromine water to each of them. Then you can recognize </span>the unsaturated compound, because as you know it will  decolourize during adding bromine water, so we can make a conclusion that it will undergo as an addition reaction. Hope you will agree with me and fing this answer helpful for you. Regards!
You might be interested in
Given 7.65 mol AgNO3, determine the number of formula units.
Komok [63]

Answer:

The number of formula units of silver nitrate is 4.61\times 10^{24}.

Explanation:

Moles of silver nitrate = n = 7.65 mol

1 mole = N_A=6.022\times 10^{23} atoms/ molecules/ ions

Let the number of formula units of silver nitrate be N.

N=n\times N_A

N=7.65 mol\times 6.022\times 10^{23}=4.61\times 10^{24}

The number of formula units of silver nitrate is 4.61\times 10^{24}.

3 0
4 years ago
What is the molarity of a 2.0 L sodium hydroxide solution containing 10.0 grams of solute? 0.80 M 0.13 M 5.0 M 0.25 M
Olenka [21]
Molarity is moles of solute per litre of solvent. We're given mass of solute, but can convert to moles using the molar mass of NaOH (40 g/mol). There are 10 g / 40 g/mol = 0.25 mol of NaOH in the solution.

M = 0.25 mol / 2.0 L = 0.125M

The second answer (0.13M) is the correct one.
5 0
4 years ago
Read 2 more answers
You were instructed to add 1.0 mL out of 4.0 mL of an undiluted sample to 99 mL of sterile diluent. Instead, you add the entire
finlep [7]

Answer:

A.) Intended dilution factor : 0.01

B.) Actual dilution factor: 0.039

Explanation:

Dilution factor(DF) is ratio of the volume of the undiluted sample to total volume of diluted solution

A.) What was your intended dilution factor

This would be the the addition 1.0ml from 4.0ml to 99ml of sterile

Volume of sterile diluent = 99ml

Volume of Undiluted sample = 1.0ml

Total volume of diluted solution = 99ml + 1m = 100ml

Dilution factor = Volume of undiluted sample ÷ Total volume of diluted solution

Dilution factor = 1:100

= 1ml ÷ 100ml

= 0.01

B.) What was your actual dilution factor?

This would be the entire addition of 4.0ml to 99ml sterile diluent

Volume of sterile diluent = 99ml

Volume of Undiluted sample = 4.0ml

Total volume of diluted solution = 99ml + 4.0ml = 103ml

Dilution factor = Volume of undiluted sample ÷ Total volume of diluted solution

Dilution factor

= 4:103

= 4ml ÷ 103ml

= 0.039

8 0
3 years ago
Why do we put these three words together in the 'fire triangle'?
bazaltina [42]
The three word of this is to represent what it takes to create and maintain a fire
7 0
3 years ago
CHEM HELP!
sweet [91]

So let's convert this amount of mL to grams:

\frac{13.6g}{1mL}*1.2mL=16.32g

Then we need to convert to moles using the molar weight found on the periodic table for mercury (Hg):

\frac{1mole}{200.59g}*16.32g=8.135*10^{-2}mol

Then we need to convert moles to atoms using Avogadro's number:

\frac{6.022*10^{23}atoms}{1mole} *[8.135*10^{-2}mol]=4.90*10^{22}atoms

So now we know that in 1.2 mL of liquid mercury, there are 4.90*10^{22}atoms present.

4 0
4 years ago
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