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slega [8]
3 years ago
8

A basic substance consisting of only one kind of atom is called a(n) _____.

Chemistry
1 answer:
juin [17]3 years ago
6 0
Answer is D) Element
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A hydrogen-like ion is an ion containing only one electron. The energies of the electron in a hydrogen-like ion are given by the
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Answer:

The ionization energy (in kJ/mol) of the helium ion is 21,004.73 kJ/mol .

Explanation:

E_n = -(2.18 10-18 J)\times \frac{Z^2}{n^2}

Z = atomic mass

n = principal quantum number

Energy of the electron in n=1,

E_1= -(2.18 10^{-18} J)\times \frac{4^2}{1^2}=-3.488\times 10^{-17} J

Energy of the electron in n = ∞

E_{\infty}= -(2.18 10^{-18} J)\times \frac{2^2}{\infty ^2}=0 J

Ionization energy of the He^+ ion:

I.E=E_{infty}-E_1=0-(-3.488\times 10^{-17} J)=3.488\times 10^{-17} J

I.E=3.488\times 10^{-20} kJ

To convert in into kj/mol multiply it with N_A=6.022\times 10^{23} mol^{-1}

I.E=3.488\times 10^{-20} kJ\times 6.022\times 10^{23} mol^{-1}=21,004.73kJ/mol

3 0
2 years ago
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You are planting flowers in large pots. You plan to plant flowers in 10 pots. 15 cups of potting soil will fill one pot. A bag o
dimaraw [331]

Answer:

I will need  six (6) bags of potting soil

Explanation:

Since you plan on planting in 10 pots and need 15 cups of potting soil per pot, the total amount of potting soil you need <em>(in cups)</em> is 10 X 15 = 150 cups of potting soil.

We have that a bag contains 25 sups. to get the number of bags needed, we have to divide 150 by 25. This will give us 150 / 25 = 6 bags.

Therefore, I will need  six (6) bags of potting soil

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3 years ago
You have 100 grams of rubidium bromide (RbBr). How many moles do you have?
Margarita [4]

Answer:

a) 0.61 mol

Explanation:

165.3718 g Rubidium Bromide = 1 mol

100 g  Rubidium Bromide =  1/165.3718  x   100

                                          =  0.61 mol

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3 years ago
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Which formula contains two nonmetals
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Answer:

Nonmetal + Nonmetal —> covalent compound (usually)

Explanation:

Covalent compounds are formed when two nonmetals react with each other.

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Create the Lewis structure of COCl2 using the following five steps. NOTE: Work only on the currently bolded step below - don't w
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