Answer:
Boil the water and stir in potassium nitrate. If it doesn't all dissolve, you can cook it on the stove or microwave it until the water boils again. Remove the solution from heat, but let it cool slowly for the best crystal formation.
I think the best answer is C. Since the light energy would be the sun and chemical energy being the glucose that feeds the plant.
Answer:
12 átomos de oxígeno hay presentes
Explanation:
Basados en la reacción:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
<em>6 moles de agua producen 1 mol de glucosa</em>
<em />
Si reaccionan 12 moleculas de agua, se producirán:
12 moleculas H₂O * (1 mol C₆H₁₂O₆ / 6 mol H₂O) =
2 moléculas de glucosa se producen.
Como cada molécula de glucosa tiene 6 átomos de oxígeno:
2 moléculas C₆H₁₂O₆ * (6 átomos Oxígeno / 1 molécula C₆H₁₂O₆) =
<h3>12 átomos de oxígeno hay presentes</h3>
Answer:
D) 2-methylpent-2-ene
Explanation:
This is an elimination reaction of Halogenoalkane. 2-bromo-2-methylpentane when is heated with NaOH or NaOC2O5( sodium ethoxide) in ethanol will form alkene rather than alcohol.
2-methylpent-1-ene is minor product since double bond form with secondary Carbon rather than primary Carbon.
