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Nookie1986 [14]
3 years ago
13

What is the function of eye lens of human eye​

Physics
1 answer:
Arte-miy333 [17]3 years ago
8 0

Answer:

the lens is located in the eye. by changing its shape, the lens changes the focal distance of the eye. in other words,it focuses the light rays that pass through it (and onto the retina) in order to create clear images of objects that are positioned

at various distances.

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Consider an ideal gas at 27.0 degrees Celsius and 1.00 atmosphere pressure. Imagine the molecules to be uniformly spaced, with e
antiseptic1488 [7]

Answer:

The length of an edge of each small cube  is 3.43 nm.

Explanation:

Given that,

Temperature of ideal gas =27.0°C

Pressure = 1.00 atm

We need to calculate the length of an edge of each small cube

Using gas equation

PV=nRT

PV=NkT

V=\dfrac{NkT}{P}

For, N = 1

Where,

N = number of molecule

k = Boltzmann constant

T = temperature

P= pressure

Put the value into the formula

V=\dfrac{1\times1.38\times10^{-23}\times(27+273)}{1.03\times10^{5}}

V=4.019\times10^{-26}\ m^3

Now, for the cube

V=L^3

L=V^{\frac{1}{3}}

L=(4.019\times10^{-26})^{\frac{1}{3}}

L=3.43\times10^{-9}\ m

L=3.43 nm

Hence, The length of an edge of each small cube  is 3.43 nm.

3 0
4 years ago
Question 8 of 10
mixas84 [53]

A. The amount of water. 50/50

5 0
3 years ago
Which be behavior of light makes it possible for you to see a spectrum of colors in a spray of water on a sunny day?
Vikentia [17]
B. Reflection (I just googled it )
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3 years ago
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The following diagram represents a cart with an initial velocity of 1.0 m/s sliding along a frictionless track from point A:
Phantasy [73]

Answer:

I believe it will it is B and D. Because they have the same shape and on both the cart wil be speeding up.

I HOPE THIS HELPS! HAVE A GREAT DAY! :)

5 0
4 years ago
It is desiredto FDM 30voice channels (each with a bandwidth of 4.5KHz) along with a guard band of 0.8KHz. Ignoring a guard band
Hitman42 [59]

Answer:

Total bandwidth required  = 158.2 KHz

Explanation:

given data:

number of channel 30

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bandwidth of guard band 0.8 KHz

According to the given information, first guard band and the guard band after last channel should be ignored, therefore we have total number of  29 guard band.

As per data, we can calculate total bandwidth  required

total bandwidth = 30*4.5 + 29*0.8

total bandwidth required  = 158.2 KHz

4 0
3 years ago
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