Answer
Pressure, P = 1 atm
air density, ρ = 1.3 kg/m³
a) height of the atmosphere when the density is constant
Pressure at sea level = 1 atm = 101300 Pa
we know
P = ρ g h
h = 7951.33 m
height of the atmosphere will be equal to 7951.33 m
b) when air density decreased linearly to zero.
at x = 0 air density = 0
at x= h ρ_l = ρ_sl
assuming density is zero at x - distance
now, Pressure at depth x
integrating both side
now,
h = 15902.67 m
height of the atmosphere is equal to 15902.67 m.
The coin will normally land on our hand.
Answer:
370.6 nm
Explanation:
wavelength in vacuum = 494 nm
refractive index of water with respect to air = 1.333
Let the wavelength of light in water is λ.
The frequency of the light remains same but the speed and the wavelength is changed as the light passes from one medium to another.
By using the definition of refractive index
where, n be the refractive index of water with respect to air
By substituting the values, we get
λ = 370.6 nm
Thus, the wavelength of light in water is 370.6 nm.
I say "Terry is correct." and "Stop looking at me !" .
To see what causes a change in experiment. If they kept everything the same what would be the point of experiment? One thing has to be different to test and get a result ! They have to see how that one variable changes the experiment. If they change so many things then the experiment will be messed up. They have to focus on that one variable during experiment to get the proper result. Hope this helps you. Think about it if you want to know how antibiotic effects bodies. You choose two people and you give antibiotic to one. And you don't give any other drug to the people you are testing. Because you truly want to know the effect of antibiotic alone.
