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12345 [234]
3 years ago
12

Acid indigestion is sometimes neutralized with an antacid such as magnesium hydroxide (Mg(OH)2). What products will be released

when the antacid is mixed with the hydrochloric acid in the stomach? *
1 point
H2O and OH
MgOH and H3O2
Cl(OH)2 and HNa
MgCl2 and H2O
Chemistry
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

It might be CI(OH) but I'm not sure

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A 250 ml solution of 2.0 M NaOH is diluted to 1.0 liter. What is the final concentration of the solution?
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Answer:

Diluted concentration is 0.5M

Explanation:

Let's solve this with rules of three, although there is a formula to see it easier

In 1000 mL (1L), we have 2 moles of NaOH

In 250 mL we must have (250 . 2) / 1000 = 0.5 moles of NaOH

These moles will be also in 1 L of the final volume of the diluted solution

More easy:

1 L of solution has 0.5 moles of NaOH

Then, molarity is 0.5 M

The formula is: Concentrated M . Conc. volume = Diluted M . Diluted volume

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4 years ago
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A 1500 L weather balloon is at 'a temperature of 290 K on the ground. As it rises the
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Answer:

1086.2 L

Explanation:

The computation of the volume of the elevation is given below:

Here we assume the volume of the elevation be x

As we know that

V¹ ÷ T¹ = V² ÷ T²

Here

V^1 = 1500

T^1 = 290

V^2 = x

T^2 = 210

Now place these values to the above formula

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3 years ago
How can you tell the number covalent bonds the atoms of an element can form?
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A covalent bond is formed between two atoms by sharing electrons. The number of bonds an element forms in a covalent compound is determined by the number of electrons it needs to reach octet.
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3 years ago
A 25.0 g piece of aluminum (which has a molar heat capacity of 24.03 J/mol°C) is heated to 86.4°C and dropped into a calorimeter
Ira Lisetskai [31]

Answer:

m H2O = 56 g

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∴ The heat ceded (-) by the Aluminum part is equal to the heat received (+) by the water:

⇒ - (mCΔT)Al = (mCΔT)H2O

∴ m Al = 25.0 g

∴ Mw Al = 26.981 g/mol

⇒ n Al = (25.0g)×(mol/26.981gAl) = 0.927 mol Al

⇒ Q Al = - (0.927 mol)(24.03 J/mol°C)(26.8 - 86.4)°C

⇒ Q Al = 1327.64 J

∴ mH2O = Q Al / ( C×ΔT) = 1327.64 J / (4.18 J/g.°C)(26.8 - 21.1)°C

⇒ mH2O = 55.722 g ≅ 56 g

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