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Alex787 [66]
3 years ago
14

What at the bottom of the ocean? take that! detailed answer!!!

Physics
2 answers:
victus00 [196]3 years ago
4 0

Answer: Essentially, no one is certain of the things that lie at the bottom of the sea. The oceans deepest darkest deep depths have proven more challenging to reach than traveling to the moon. In all of human history, 12 people have reached the moon, while only three have reached the bottom of the deepest part of the ocean: the Challenger Deep. The deepest point- located within the Marina Trench, reaches nearly 10,000 meters deep- beyond the depths which light can reach.

Explanation:

Alik [6]3 years ago
3 0

Answer:

Unlike mapping the land, we can't measure the landscape of the sea floor directly from satellites using radar, because sea water blocks those radio waves. But satellites can use radar to measure the height of the sea's surface very accurately.

Explanation:

94 percent of the ocean is still unexplored so thats it

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Compare and contrast scientific inquiry "skill and process".
Dmitrij [34]

Answer:

The inquiry process takes advantage of the natural human desire to make sense of the world... This attitude of curiosity permeates the inquiry process and is the fuel that allows it to continue. Process skills are not used for their own sake.

3 0
3 years ago
What is the composition of the moon, how does it compare to the composition of earth and mercury?
amm1812

Explanation:

The moon is the earth satellite and it orbits our blue planet. Earth, moon and mercury are all rock materials in the solar system. They are all made up of dense silicate balls of rocks.

  • The Earth and Mercury are made up of silicate minerals and some iron core but the moon is predominant made up of silicate balls.
  • The earth has liquid water on it's surface but the moon has no liquid water.
  • The earth is an active planet in terms of tectonic activity. The moon is not active tectonically.

Learn more:

moon brainly.com/question/12785992

#learnwithBrainly

7 0
3 years ago
while test flying the new f-22 raptor fighter jet, test pilot bob put the plane in a horizontal loop while flying at the speed o
sveticcg [70]

Given

v = 343 m/s

ac = 5g

ac = 5*9.8 m/s^2

ac = 49 m/s^2

where,

v: velocity

ac = centripetal aceleration

Procedure

We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration ac; centripetal means “toward the center” or “center seeking”.

Formula

\begin{gathered} a_c=\frac{v^2}{r} \\ r=\frac{v^2}{a_c} \\ r=\frac{(343m/s)^2}{49m/s^2} \\ r=2401\text{ m} \end{gathered}

The minimum radius not to exceed the centripetal acceleration is 2401 m.

8 0
1 year ago
If the car went 30 km west in 25 min. and then 40 km south in 35 min., what would be its average speed?
Alika [10]
The total distance is 70km.
The total time is 60 minutes or 1 hour.
Speed=Distance÷Time
=70÷1
=70km/h
8 0
3 years ago
Read 2 more answers
An object of mass, m1 with a velocity, v1 collides with another object at rest (v2 = 0) with a mass, m2. After the collision, m1
goblinko [34]

Answer:

v"_{1} = v_{1} tanΘ

v^{"} _{2} = \frac{m_{1}v_{1}}{m_{2}cos}Θ

Θ = tan^{-1}(\frac{v^{"} _{1} }{v_{1} } )

Explanation:

Applying the law of conservation of momentum, we have:

Δp_{x = 0}

p_{x} = p"_{x}

m_{1}v_{1} = m_{2}v"_{2} cosΘ (Equation 1)

Δp_{y} = 0

p_{y} = p"_{y}

0 = m_{1} v"_{1} - m_{2} v"_{2} sinΘ (Equation 2)

From Equation 1:

v"_{2} = \frac{m_{1}v_{1}}{m_{2}cos}Θ

From Equation 2:

m_{2} v"_{2}sinΘ = m_{1} v_{1}

v"_{1} = \frac{m_{2} v"_{2}sinΘ}{m_{1} }

Replacing Equation 3 in Equation 4:

v"_{1}=\frac{m_{2}\frac{m_{1}v_{1}}{m_{2}cosΘ}sinΘ}{m_{1}}

v"_{1}=v_{1}\frac{sinΘ}{cosΘ}

v"_{1}=v_{1}tanΘ (Equation 5)

And we found Θ from the Equation 5:

tanΘ=\frac{v"_{1}}{v_{1}}

Θ=tan^{-1}(\frac{v"_{1}}{v_{1}})

7 0
3 years ago
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