A student wants to determine the impulse delivered to the lab cart when it runs into the wall. The student measures the mass of
1 answer:
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Answer:
Explanation:
A)
W = work done by the freezer = 800 J
Q = heat removed from the freezer = 1735 J
Q' = Heat expelled into the room
Coefficient of performance is given as
inserting the values
B)
Heat expelled is given as
Q' = W + Q
Q' = 800 + 1735
Q' = 2535 J
Answer:
a)6.34 x W/m²
b)1.37 x W/m²
c) see explanation.
Explanation:
a)The relation of intensity'I' of the radiation and area 'A' is given by:
I= P/A
where P= power of sunlight i.e 3.9 x J
and the area of the sun is given by,
A= 4π => 4π
A=6.15 x m²
= 3.9 x
/ 6.15 x
=><u> 6.34 x </u>
<u>W/m²</u>
b) First determine the are of the sphere in order to determine intensity at the surface of the virtual space
A= 4π
Now R= 1.5 x m
A= 4π x 1.5 x =>2.83 x
m²
The power that each square meter of Earths surface receives
= 3.9 x
/2.83 x
=><u>1.37 x </u>
<u> W/m²</u>
<u />
c) in part (b), by assuming the shape of the wavefront of the light emitted by the Sun is a spherical shape so each point has the same distance from the source i.e sun on the wavefront.