In a Physics 111 laboratory experiment, a cart with a mass of 0.80 kg and a velocity of 0.50 m/s collides elastically into a sta
1 answer:
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Answer:
Y = 0.0254 m = 25.4 mm
Explanation:
The formula for the fringe spacing in Young's Double-slit experiment is given by the following formula:
where,
Y = fringe spacing = 0.0176 m
λ = wavelength = 425 nm = 4.25 x 10⁻⁷ m
L = Distance between screen and slits
d = slit separation
Therefore,
Now, for:
λ = 614 nm = 6.14 x 10⁻⁷ m
<u>Y = 0.0254 m = 25.4 mm</u>
Answer:
A.The spring constant for B is one quarter of the spring constant for A.
Explanation:
If spring A oscillates at twice the frequency of spring B, and period is frequency inverted. It means spring B has a period twice of spring A's.
As , and the 2 springs have the same mass
So A.The spring constant for B is one quarter of the spring constant for A. is the correct answer.