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Leya [2.2K]
4 years ago
15

John bounces a ball off the ground, and it leaves the ground with a velocity of 10 m/s. How long will it take the ball to reach

maximum height?

Physics
2 answers:
Maksim231197 [3]4 years ago
8 0

Explanation:

This is true because at maximum height, the velocity is 0

wariber [46]4 years ago
3 0

Gravity makes an upward-moving object move 9.8 m/s slower every second.

So if it leaves the ground at 10 m/s, it'll run out of upward speed in

(10 m/s) / (9.8 m/s²)  =  <em>1.02 seconds </em>

At that time, since it has no more upward speed, it'll start falling. So at that instant, it was exactly at its maximum height.

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In Scientific Notation, numbers are written in the form a x 10b . In this form, b is called the
ivann1987 [24]

Answer:

b is called the power of base 10.

Explanation:

In the scientific notation form  

a\,\,10^b

the exponent b is called the power of the base 10.

3 0
3 years ago
on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. what is the velocity (speed and direction)
kiruha [24]

Velocity is the rate of change of position of an object. The velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

<h3>What is Velocity?</h3>

Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.

Given that on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. Therefore, the velocity of the air relative to the runner can be written as,

Relative velocity = √[(Velocity of the jogger)² + (Velocity of the air)²]

                            = √[(5)² + (5)²]

                            = √(25 + 25)

                            = √50

                            = 5√2 m/sec

The direction of the relative velocity is,

The angle of relative Velocity = Tan(θ)

Tan(θ) = Vertical velocity / Horizontal velocity

Tan(θ) = 5/5

Tan(θ) = 1

θ = tan⁻¹(1)

θ = 45°

Since this angle is formed between the two velocities, therefore, the direction of the velocity is southwest.

Hence, the velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

Learn more about Velocity here:

brainly.com/question/18084516

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4 0
1 year ago
What change of state occurs during vaporization
seraphim [82]
The liquid state into a gaseous state
3 0
3 years ago
Read 2 more answers
2. Why was it important to examine both the color and the streak of your minerals? Think about streak and explain why it’s calle
horrorfan [7]
<span>Some minerals might have similar color, but different streaks. Others might have the same streak color, but different colors</span>
3 0
3 years ago
The lever PQ is welded to the bent rod QSTU which is supported by a single thrust bearing at S and by the rigid link UV. Link UV
valentinak56 [21]

Answer:

The answer to the questions are as follows

a) The magnitude of the force in UV = 512.41 N

b) The five support reaction components are

1. PQ turning moment force about the z axis

2. PQ turning moment force about the y axis

3. UV turning moment force about the y axis

4. UV turning moment force about the z axis

5. UV turning moment force about the x axis

Please see below

Explanation:

When the system is in 3D equilibrium

Sum of forces in x direction = 0

Sum of forces in y direction = 0

Sum of forces in z direction = 0

Also, Sum of moments in x direction = 0

Sum of moments in y direction = 0

Sum of moments in z direction = 0

From the diagram, we have force in the +ve x direction = 600 N

Also moment about y = 600×0.08 = 48 Nm

Moment about z = 600×0.09 = -54 Nm

Moment about x, = 0 Nm

For the support S, taking moment about x = 0.05 × S

taking moment about y = 0

taking moment about z = 0

At point U, taking moment about y = -0.1U

moment about x = -0.05U

moment about z = -0.1U

Summing the moments we have

In the x, y and z directions

0 + 0.04Vy-1.46Vz -0.05Uz= 0.... (1)

48 + 0.1Vz-0.04Vx - 0.1Uz = 0... (2)

-24 + 0.146Vx-0.1Vy + 0.05Ux + 0.01Uy = 0.... (3)

Ux + Vx = 600  ....(4)

Uy = -Vy .....(5)

Uz = -Vz .......(6)

Solving the above 6 equations we get the following values

Ux = 242.28 N

Uy = -366.74

Uz = -10.40

Vx = 357.72N

Vy = 366.74N

Vz = 10.40N

The magnitude of the force in UV = \sqrt{357.72^{2} + 366.74^{2} + 10.40^{2} } = 512.41 N

b) The five support reaction components are

1. PQ turning moment force about the z axis

2. PQ turning moment force about the y axis

3. UV turning moment force about the y axis

4. UV turning moment force about the z axis

5. UV turning moment force about the x axis

5 0
4 years ago
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