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Leya [2.2K]
4 years ago
15

John bounces a ball off the ground, and it leaves the ground with a velocity of 10 m/s. How long will it take the ball to reach

maximum height?

Physics
2 answers:
Maksim231197 [3]4 years ago
8 0

Explanation:

This is true because at maximum height, the velocity is 0

wariber [46]4 years ago
3 0

Gravity makes an upward-moving object move 9.8 m/s slower every second.

So if it leaves the ground at 10 m/s, it'll run out of upward speed in

(10 m/s) / (9.8 m/s²)  =  <em>1.02 seconds </em>

At that time, since it has no more upward speed, it'll start falling. So at that instant, it was exactly at its maximum height.

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Examine the circuit. Pretend you are an electron flowing through this circuit and you are with a group of other electrons. Sudde
melamori03 [73]

You knew that this question is ridiculously easy.  So, just to
make it harder, you decided not to let us see the picture, so
that we could not "examine the circuit".

The description is talking about a parallel circuit.  The other
kind is a series circuit, and that one has no forks in the road.
7 0
3 years ago
Read 2 more answers
two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel .calculate the equivalent series resist
Novosadov [1.4K]

Explanation:

Given that,

Two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel.

For series combination,

R_{eq}=R_1+R_2

For parallel combination,

\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}

When 6 ohm and 3 ohm are in series,

R_s=6+3\\\\R_s=9\ \Omega

When 6 ohm and 3 ohm are in paralle,

\dfrac{1}{R_p}=\dfrac{1}{6}+\dfrac{1}{3}\\\\R_p=2\ \Omega

So, the equivalent resistance in series combination is 9 ohms and in parallel combination it is 2 ohms.

6 0
3 years ago
Which career professionals are part of the Architecture and Construction career cluster? Check all that apply.
oksian1 [2.3K]

Answer:

A,B,D,E,F

Explanation:

I took the test for yall.

3 0
3 years ago
A uniformly charged rod (length = 2.0 m, charge per unit length = 3.0 nc/m) is bent to form a semicircle. What is the magnitude
Artist 52 [7]

Answer:

84.82N/C.

Explanation:

The x-components of the electric field cancel; therefore, we only care about the y-components.

The y-component of the differential electric field at the center is

$dE = \frac{kdQ }{R^2} sin(\theta )$.

Now, let us call \lambda the charge per unit length, then we know that

dQ = \lambda Rd\theta;

therefore,

$dE = \frac{k \lambda R d\theta }{R^2} sin(\theta )$

$dE = \frac{k \lambda  d\theta }{R} sin(\theta )$

Integrating

$E = \frac{k \lambda   }{R}\int_0^\pi sin(\theta )d\theta$

$E = \frac{k \lambda   }{R}*[-cos(\pi )+cos(0) ]$

$E = \frac{2k \lambda   }{R}.$

Now, we know that

\lambda = 3.0*10^{-9}C/m,

k = 9*10^9kg\cdot m^3\cdot s^{-4}\cdot A^{-2},

and the radius of the semicircle is

\pi R = 2.0m,\\\\R = \dfrac{2.0m}{\pi };

therefore,

$E = \frac{2(9*10^9) (3.0*10^{-9})   }{\dfrac{2.0}{\pi } }.$

$\boxed{E = 84.82N/C.}$

7 0
3 years ago
A 0.0600-kilogram ball traveling at 60.0 meters
Vikki [24]
     The momentum of ball is given by:

\Delta Q=mv \\ \Delta Q=6*10^{-2}*60 \\ \Delta Q=3.6kg*m/s
  
     Since both have the same momentum, we have:

\Delta Q=MV \\ 3.6=10^{-2}V \\ \boxed {V=360m/s}

Number 3

If you notice any mistake in my english, please let me know, because i am not native.    

7 0
3 years ago
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