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Alborosie
3 years ago
6

A proton moving at 8.9 × 106 m/s through a magnetic field of 0.96 T experiences a magnetic force of magnitude 3.8 × 10−13 N. Wha

t is the angle between the proton’s velocity and the field? The charge on a proton is 1.60218 × 10−19 C and its mass is 1.67262 × 10−27 kg.
Physics
1 answer:
goblinko [34]3 years ago
8 0

Answer: 15.66 °

Explanation: In order to solve this proble we have to consirer the Loretz force for charge partcles moving inside a magnetic field. Thsi force is given by:

F=q v×B = qvB sin α where α is teh angle between the velocity and magnetic field vectors.

From this expression and using the given values we obtain the following:

F/(q*v*B) = sin α

3.8 * 10^-13/(1.6*10^-19*8.9*10^6* 0.96)= 0.27

then  α =15.66°

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Joint committees have similar purposes as select committees, but they are made up of members from both the House and the Senate. They are set up to conduct business between the houses and to help focus public attention on major issues.
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3 years ago
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A runner moves 2.88 m/s north. She accelerates at 0.350 m/s^2 at a -52.0 angle. At the point in the motion where she is running
MrRissso [65]

The runner has initial velocity vector

\vec v_0=\left(2.88\dfrac{\rm m}{\rm s}\right)\,\vec\jmath

and acceleration vector

\vec a=\left(0.350\dfrac{\rm m}{\mathrm s^2}\right)(\cos(-52.0^\circ)\,\vec\imath+\sin(-52.0^\circ)\,\vec\jmath)

so that her velocity at time t is

\vec v=\vec v_0+\vec at

She runs directly east when the vertical component of \vec v is 0:

2.88\dfrac{\rm m}{\rm s}+\left(0.350\,\dfrac{\rm m}{\mathrm s^2}\right)\sin(-52.0^\circ)\,t=0\implies t=10.4\,\rm s

It's not clear what you're supposed to find at this particular time... possibly her position vector? In that case, assuming she starts at the origin, her position at time t would be

\vec x=\vec v_0t+\dfrac12\vec at^2

so that after 10.4 s, her position would be

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3 years ago
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The Earth can be approximated as a sphere of uniform density, rotating on its axis once a day. The mass of the Earth is 5.97×102
svetlana [45]

Answer:

I = 97.2 10³⁶ kg m²

Explanation:

The moment of inertia of a body the expression of inertia in the rotational movement and is described by the expression

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In this problem we are told to use the moment of inertia of a uniform sphere, the expression of this moment of inertia is

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where m is the mass of the earth and r is the radius of the earth.

Let's calculate

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      I = 97.2 10³⁶ kg m²

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Answer:

The time it takes light to cover 1.5 km was too short to be measured by Galileo's instruments.

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The speed of light is c=3*10^8m/s, which means the time it takes to cover a distance of 1.5 km (or 1,500m) will be

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An object in motion tends to stay in motion an oject at rest stays at rest.
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