4. Premature wrinkling due to overexposure to the Sun, what am I?

What is the formula of Acceleration for mass and time

GarryVolchara [31]

Answer:

a = m/t²

Explanation:

The Formula of Acceleration for mass and time

a = m/t²

where,

m = meter

t = time in (seconds)

The SI unit of acceleration is m/s² or ms⁻²

-TheUnknownScientist

5 0

3 years ago

A particle with charge − 3.74 × 10 − 6 C is released at rest in a region of constant, uniform electric field. Assume that gravit

dalvyx [7]

Answer:

57.5022228905 s

Explanation:

$V_i$ = Initial voltage

$V_f$ = Final voltage = 0.401 V

$t_1$ = Initial time = 8.36 s

$t_2$ = Final time

K = Kinetic Energy = $3.18\times 10^{-8}\ J$

C = Charge = $3.74\times 10^{-6}\ C$

Voltage is given by

$V=\dfrac{K}{C}\\\Rightarrow V=\dfrac{3.17\times 10^{-8}}{3.74\times 10^{-6}}\\\Rightarrow V=0.00847593582888\ V$

We have the relation

$\dfrac{V_i}{V_f}=(\dfrac{t_i}{t_f})^2\\\Rightarrow t_f=\sqrt{\dfrac{t_i^2V_f}{V_i}}\\\Rightarrow t_f=\sqrt{\dfrac{8.36^2\times 0.401}{0.00847593582888}}\\\Rightarrow t_f=57.5022228905\ s$

The time taken is 57.5022228905 s

4 0

3 years ago

Seeing yourself in the mirror is an example of ____ reflection. A.)light B.)particle

babunello [35]

I’m pretty sure light. But I’m not 100% sure

7 0

4 years ago

Read 2 more answers

Which of the following criteria can help Linda classify gases as greenhouse gases? gas molecules having three or more atoms gas

ratelena [41]

I think the correct answer would be the third option. The criteria that could help Linda in classifying whether the gases are greenhouse gases would be gas molecules having at least one oxygen atom. Most of the greenhouse gases has an oxygen atom in their structures especially those that naturally occurs. These gases are CO2, H2O vapor and nitrous oxide.

7 0

3 years ago

Read 2 more answers

A 5 kg object is moving in a straight-line with an initial speed of v m/s. It takes 13 s for the speed of the object to increase

coldgirl [10]

The object's kinetic energy changes according to

dK/dt = 15 J/s

If v is the object's initial speed, then its initial kinetic energy is

K (0) = 1/2 (5 kg) v ²

Use the fundamental theorem of calculus to solve for K as a function of time t :

$K(t) = K(0) + \displaystyle\int_0^t \left(15\frac{\rm J}{\rm s}\right)\,\mathrm du = \dfrac12 (5\,\mathrm{kg}) v^2 + \left(15\dfrac{\rm J}{\rm s}\right)t$

After t = 13 s, the object's kinetic energy is

K (13 s) = 1/2 (5 kg) (13 m/s)² = 422.5 J

Put this as the left side in the equation above for K(t) and solve for v :

$422.5\,\mathrm J = \dfrac12 (5\,\mathrm{kg}) v^2 + \left(15\dfrac{\rm J}{\rm s}\right)(13\,\mathrm s)$

==> v ≈ 9.5 m/s

8 0

3 years ago

4. Premature wrinkling due to overexposure to the Sun, what am I?​

4. Premature wrinkling due to overexposure to the Sun, what am I?