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Serhud [2]
2 years ago
12

"On a good day, it takes Mr. Hess 23 minutes (1380 seconds) to drive the 12 miles (19,300 meters). What is his average velocity

on the way to school?"
I uh, don't understand this at all. If someone could help me solve this, I'd greatly appreciate it!
Physics
1 answer:
il63 [147K]2 years ago
5 0

Answer:

his average velocity is

v =  \frac{19300}{1380}  = 13.9855(m \div s)

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If you were to drive an average velocity of 65 mi/hr to Traverse City, which is
Amanda [17]
Find the number of hours by dividing the distance by mph. The number of hours will be to the left of the decimal point:

250 miles / 65 mph
= 3.846153846
= 3 hours

2) Find the number of minutes by multiplying what is remaining from step 1 by 60 minutes. The minutes will be to the left of the decimal point:

0.846153846 x 60
= 50.76923076
= 50 minutes

3) Find the number of seconds by multiplying what is remaining from step 2 by 60 seconds. The seconds will be to the left of the decimal point:

0.76923076 x 60
= 46.1538456
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So 3 hours 50 mins and 46 seconds
3 0
2 years ago
Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.
alexandr1967 [171]

Answer:

v=\sqrt{k\frac{e^2}{m_e r}}, 2.18\cdot 10^6 m/s

Explanation:

The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

r is the distance between the electron and the nucleus

v is the speed of the electron

m_e is the mass of the electron

Solving for v, we find

v=\sqrt{k\frac{e^2}{m_e r}}

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

r=5.3\cdot 10^{-11}m

while the electron mass is

m_e = 9.11\cdot 10^{-31}kg

and the charge is

e=1.6\cdot 10^{-19} C

Substituting into the formula, we find

v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s

7 0
3 years ago
PLEASE HELP!!! FIRST IS BRAINLIEST!!!
Verizon [17]
1. A Medium

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3. </span>properties and nature of medium, Hope this helps.
6 0
3 years ago
Read 2 more answers
Through which one of the following mediums is the velocity of a sound wave the greatest?
Colt1911 [192]

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<em><u>through steel (which is almost perfectly elastic) is about</u></em>

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6 0
2 years ago
A light bulb will glow when electrons flow through it. As the electron flow increases, the brightness increases as well. A stude
SIZIF [17.4K]

Answer:

Please find the answer in the explanation

Explanation:

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If you could only see the lights in the circuit and the wires were covered up, how could you tell the type of circuit?

The type of the circuit can be determined if you loose or unscrew one light bulb, all other bulbs will be switched of if connected in series. But if the others remain on it is a parallel circuit.

5 0
3 years ago
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