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3 years ago

Name one process that requires a force in the human body.

Physics

2 answers:

vova2212 [387]3 years ago

8 0

Non-contact force, which Is a force that acts like an object without coming in physically contact with you

allsm [11]3 years ago

5 0

muscle contraction, blood circulation

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Please need help on this I know it’s not D an atom.

Alchen [17]

A reactant since it is on the left of the arrow

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3 years ago

Question 2 An ideal gas in a piston/cylinder device is compressed at constant temperature. The entropy of the ideal gas will:

Flura [38]

To solve the problem it is necessary to refer to the definition of entropy.

Entropy is defined aso

$\Delta S = \frac{\Delta Q}{T}$

Where,

$\Delta Q =$ Heat exchange

T = Temperature

Since the heat exchange is conserved and it is an isothermal process where the temperature remains constant the change in entropy remains the same, ie $\Delta S = 0$ (Reamins same)

Therefore the correct answer is C.

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4 years ago

3. Suppose that an airplane flying 60 m/s, at a height of 300m, dropped a sack of flour (pere the effect

Arlecino [84]

469.24m. An airplane flying 60m/s at a height of 300m dropped a sack of flour that stack the ground 469.24m from the point of release.

This is a example of horizontal parabolic projectile motion,and we represents this motion in the coordinate axis, which means that the velocity has components in x axis and y axis.

The equation of components on the x axis.

$v_{0}x=\frac{x}{t}$ , where x is the distance and Vox the initial velocity before the drop

The equation of components on the y axis.

$y = v_{0}yt+\frac{gt^{2} }{2}$ , where y is the height, and the velocity in y component before the drop is 0, reducing the equation to $y = \frac{gt^{2} }{2}$

Clear t from both the equation of components on the x axis and the y axis:

$t=\frac{x}{v_{0} x}$ and $t=\sqrt{\frac{2h}{g}}$

Equating both equations and clearing the distance x:

$\frac{x}{v_{0} x}=\sqrt{\frac{2h}{g}}\\x={v_{0} x}\sqrt{\frac{2h}{g}}$

Substituting the values:

$x=60\frac{m}{s} \sqrt{\frac{2(300m)}{9.81\frac{m}{s^{2} } }}=469.24m$

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3 years ago

The particles of a substance can have kinetic energy (KE) and potential energy (PE). Which equation best summarizes the internal

Olenka [21]

Answer:

The internal energy of a substance is equal to the total amount of potential energy and kinetic energy of ALL the particles in the substance.

For example, when the temperature increases (more temperature means more energy), the kinetic energy of the particles in the substance increases.

And when we reach a point near a change of phase (like near fusion point) there is energy used to break the bonds between the particles, then we have an increase in potential energy.

Then we could write the internal energy as:

U = ∑(KEₙ) + ∑(PEₙ)

Where ∑(KEₙ) and ∑(PEₙ) are the sums of the kinetic energy and potential energy of all the particles in the substance.

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3 years ago

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An air mass gets its temperature and humidity characteristics from

nikklg [1K]

The atmosphere....................................

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3 years ago