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Rasek [7]
3 years ago
15

In general, an atom with _________________ electrons in its valence shell tends to lose electrons and form a ___________________

charged ion. An atom with __________________ electrons in its valence shell tends to _________________ electrons and form a _______________ charged ion.
Chemistry
1 answer:
Tatiana [17]3 years ago
7 0

Explanation:

When an atom tends to gain an electron then it forms a negatively charged ion. Whereas when an atom tends to lose an electron then it acquires a positive charge.

For example, any element having more than eight electrons in its valence shell will tend to lose electron(s).

And, any element having less than eight electrons will tend to gain electron(s).

Thus, we can conclude that in general, an atom with more than eight electrons in its valence shell tends to lose electrons and form a positively charged ion. An atom with less than eight electrons in its valence shell tends to gain electrons and form a negatively charged ion.

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Carbon tetrachloride, CCl4, was once used as a dry cleaning solvent, but is no longer used because it is carcinogenic. At 57.8 °
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This problem is to use the Claussius-Clapeyron Equation, which is:

ln [p2 / p1] = ΔH/R [1/T2 - 1/T1]

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ΔH is the enthalpy of vaporization

R is the universal constant of gases = 8.314 J / mol*K

T2 and T1 are the temperatures at the estates 2 and 1.

The  normal boiling point => 1 atm (the pressure of the atmosphere at sea level) = 101,325 kPa

Then p2 = 101.325 kPa
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p1 = 54.0 kPa
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=> ln [101.325/54.0] = [ (33,050 J/mol) / (8.314 J/mol*K) ] * [1/x - 1/330.95]

=> 0.629349 = 3975.22 [1/x - 1/330.95] = > 1/x =  0.000157 + 1/330.95 = 0.003179

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Answer:

0.46 grams (C₆H₅)₂CO

Explanation:

To find the mass of benzophenone ((C₆H₅)₂CO), you need to (1) convert mmoles to moles and then (2) convert moles to grams (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units. The final answer should have 2 sig figs to match the sig figs of the given value (2.5 mmoles).

Molar Mass ((C₆H₅)₂CO): 13(12.011 g/mol) + 10(1.008 g/mol) + 15.998 g/mol

Molar Mass ((C₆H₅)₂CO): 182.221 g/mol

2.5 mmoles (C₆H₅)₂CO               1 mole                  182.221 g
-----------------------------------  x  ------------------------  x  -------------------  =
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=  0.46 grams (C₆H₅)₂CO

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