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2 years ago

Which is one factor that contributes to the formation of polar, temperate, and tropical zones?

Physics

1 answer:

Tju [1.3M]2 years ago

4 0

Answer:

The angle of the Sun's rays:

At about June 21 the sun is directly overhead at about 23 deg north of the equator

On about Dec 21 the sun is directly overhead at about 23 deg south of the equator

It is this tilt 23 deg to the ecliptic (path of earth about sun) that causes the major temperature changes on earth

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A 100-kg spacecraft is in a circular orbit about Earth at a height h = 2RE .

maria [59]

To solve this problem it is necessary to apply the concepts related to the conservation of the Gravitational Force and the centripetal force by equilibrium,

$F_g = F_c$

$\frac{GmM}{r^2} = \frac{mv^2}{r}$

Where,

m = Mass of spacecraft

M = Mass of Earth

r = Radius (Orbit)

G = Gravitational Universal Music

v = Velocity

Re-arrange to find the velocity

$\frac{GM}{r^2} = \frac{v^2}{r}$

$\frac{GM}{r} = v^2$

$v = \sqrt{\frac{GM}{r}}$

PART A ) The radius of the spacecraft's orbit is 2 times the radius of the earth, that is, considering the center of the earth, the spacecraft is 3 times at that distance. Replacing then,

$v = \sqrt{\frac{(6.67*10^{-11})(5.97*10^{24})}{3*(6.371*10^6)}}$

$v = 4564.42m/s$

From the speed it is possible to use find the formula, so

$T = \frac{2\pi r}{v}$

$T = \frac{2\pi (6.371*10^6)}{4564.42}$

$T = 8770.05s\approx 146min\approx 2.4hour$

Therefore the orbital period of the spacecraft is 2 hours and 24 minutes.

PART B) To find the kinetic energy we simply apply the definition of kinetic energy on the ship, which is

$KE = \frac{1}{2} mv^2$

$KE = \frac{1}{2} (100)(4564.42)^2$

$KE = 1.0416*10^9J$

Therefore the kinetic energy of the Spacecraft is 1.04 Gigajules.

8 0

3 years ago

[]Answer the question below[]

marysya [2.9K]

Answer:

The answer is D. density.

8 0

2 years ago

a wave in a rope is traveling at 6 m/s and at a frequency of 2 Hz. what is the wavelength of the wave producced

Tems11 [23]

Answer:

Explanation:

4 0

3 years ago

Describe how pieces of rope move as waves pass

MaRussiya [10]

Well, as the waves move it moves the rope as if its trying to take shape of it. Since the rope it light it will move along the ocean and the ocean will keep pushing up on the rope. (even without the waves the water is pushing the rope up so it can take its shape)

Maybe that'll help

6 0

3 years ago

You make the following measurements of an object 42kg and 22m3 what would the objects density be

miv72 [106K]

The density of the object is approximately 1.91 kg per m³.

42 kg is a measure of mass, and 22 m³ is a measure of volume. Knowing this, you can use the relationship $density = mass / volume$ to solve for the object's density.

42 kg $\div$ 22 m³ $\approx$ 1.91 kg per m³.

4 0

3 years ago

Read 2 more answers