Question

A 4-m long wire with a mass of 40 g is under tension. A transverse wave for which the frequency is 860 Hz, the wavelength is 0.5 m, and the amplitude is 6.7 mm is propagating on the wire. The maximum transverse acceleration of a point on a wire is closest to

Answer 1

Answer:

Maximum acceleration will be $195372m/sec^2$    

Explanation:

It is given mass m =40 gram = 0.04 kg

Length of the wire l = 4 m

Frequency of transverse wave f = 860 Hz

Wavelength $\lambda =0.5m$

Amplitude of the propagating wave $A=6.7mm=0.0067m$

Angular frequency is equal to $\omega =2\pi f=2\times 3.14\times 860=5400rad/sec$

Maximum acceleration is equal to $a=\omega ^2A=5400^2\times 0.0067=195372m/sec^2$

So maximum acceleration will be $195372m/sec^2$