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gulaghasi [49]
2 years ago
14

Why is Pluto no longer a planet?

Physics
2 answers:
Tema [17]2 years ago
7 0

Answer:

Scientist thought it was to small to be a planet.

Explanation:

it's sad, it was my favorite planet. now it's my favorite dwarf planet.

Step2247 [10]2 years ago
5 0
The International Astronomical Union (IAU) downgraded the status of Pluto to that of a dwarf planet because it did not meet the three criteria the IAU uses to define a full-sized planet. Essentially Pluto meets all the criteria except one—it “has not cleared its neighboring region of other objects.
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Consider a transition at 5000 Å with a width of 1 Å and a cavity 2 cm3 in volume. How many electromagnetic modes exist in this f
Lena [83]

Answer:

total number of modes is 8

Explanation:

attached here is the calculations

3 0
3 years ago
A bullet is fired with a velocity of 100 m/s from the ground at an angle of 60° with the horizontal. Calculate the horizontal ra
seraphim [82]

1) The horizontal range of the bullet is 884 m

2) The maximum height attained by the bullet is 383 m

Explanation:

1)

The motion of the bullet is a projectile motion, which consists of two separate motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

From the equation of motions along the x- and y- directions, it is possible to find an expression for the horizontal range covered by a projectile, and it is:

d=\frac{u^2 sin 2\theta}{g}

where

u is the initial speed of the projectile

\theta is the angle of projection

g=9.8 m/s^2 is the acceleration of gravity

For the bullet in the problem, we have

u = 100 m/s (initial speed)

\theta=60^{\circ} (angle)

Solving the equation, we find the horizontal range:

d=\frac{(100)^2sin(2\cdot 60^{\circ})}{9.8}=884 m

2)

To find the maximum height, we have to analyze the vertical motion of the bullet. We can do it by using the following suvat equation:

v_y^2 - u_y^2 = 2as

where

v_y is the vertical velocity of the bullet after having covered a vertical displacement of s

u_y is the initial vertical velocity

a =-g= is the acceleration (negative, since it points downward)

The vertical component of the initial velocity is given by

u_y = u sin\theta

Also, the maximum height s is reached when the vertical velocity becomes zero,

v_y =0

Substituting into the equation and re-arranging for s, we find the maximum height:

s=\frac{u^2 sin^2 \theta}{2g}=\frac{(100)^2(sin 60^{\circ})^2}{2(9.8)}=383 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

3 0
3 years ago
Select the correct answer.
Morgarella [4.7K]
D all of them is the answer. All three can be used to celebrate sporting events
3 0
2 years ago
A large truck is moving at 22.0 m/s. if its momentum is 125,000 kg • meters per second, what is the truck's mass? 176 kg 2750 kg
solong [7]

The  mass of the large truck is determined as 5680 kg.

<h3>Mass of the truck</h3>

The mass of the truck is calculated as follows;

P = mv

where;

  • P is momentum
  • m is mass
  • v is velocity

m = P/v

m = 125000/22

m = 5680 kg

Thus, the  mass of the large truck is determined as 5680 kg.

Learn more about momentum here: brainly.com/question/7538238

#SPJ1

7 0
1 year ago
Plzzzz helpppppppo Near the end of the life cycle of a star why does the star lose its size
gavmur [86]

Answer:

Because the energy is waning

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