For an airplane whose speed is 60 m/s is flying at an altitude of 500 m over the ocean toward a stationary sinking ship, the horizontal distance is mathematically given as
x=606m
<h3> What horizontal distance from the ship should the crew of the airplane drop a pump into the water next to the ship?</h3>
Generally, the equation for the y axis distance is mathematically given as
y=vt+0.5gt^2
Therefore
500=0t+1.2(9.8)t^2
t=10.1s
In conclusion, the horizontal distance
x=vt
x=60*10.1
x=606m
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PET allows for scanning of the body for diseases. MRI scans are used to form pictures of selected body parts in order to diagnose injuries. Radioimmunotherapy is used primarily to treat certain types of cancers. Nuclear Fusion involves the creation of energy using complex atomic processes.
A) Nuclear Fusion is the only choice on this list without a direct relation to medicine.
Answer:
a. 5.88 N
b. 5.09 N
Explanation:
<em>Check attachment for drawings of the free-body diagrams.</em>
(a) As we can see on our free-body diagram, the weight force and the normal force are the only forces acting on the y-direction.
Since the bullfrog is in a state of equilibrium, due to it being at rest, we can say that the weight force and normal force are equal to each other.
The weight force w is equal to mg, so we can plug the weight of the frog (0.60 kg) and the force of gravity (9.8 m/s²) to find the weight force.
- w = mg
- w = (0.60 kg)(9.8 m/s²)
- w = 5.88 N
The normal force and the weight force are equal to each other; therefore, the normal force is also equal to 5.88 N.
(b) As seen on the free-body diagram, the two forces that are in the y-direction are the normal force and the y-component of the weight force.
Therefore, by finding the force of the y-component of the weight force, we can find the normal force since they are equal to each other because the bullfrog is not moving up or down.
- F_y = n - w cos(30) = 0
- F_y = n = w cos(30)
We know that the weight force is equal to 5.88 N, so we can plug this value into the y-component for the weight force:
- w cos(30)
- 5.88 * cos(30) = 5.09 N
Since the y-component of the weight force and the normal force are equal to each other, the normal force is also equal to 5.09 N.
Answer:
Kelvin = Celsius + 273.15. Instead of 273.15 the value of 273 is also used.
Explanation:
im not sure if this is correct i have not done this in a long time but i hope it helps.