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3 years ago

11

Which of the following is an example of an irregular meter? A. Four beats per measure B. Five beats per measure C. Two beats per

measure D. Three beats per measure

1 answer:

Komok [63]3 years ago

7 0

B. 5 beats per measure.

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A ship maneuvers to within 2.46×10³ m of an island’s 1.80 × 10³ m high mountain peak and fires a projectile at an enemy ship 6.1

Nesterboy [21]

Answer:

The distance close to the peak is 597.4 m.

Explanation:

Given that,

Distance of the first ship from the mountain $d=2.46\times10^{3}\ m$

Height of island $h=1.80\times10^{3}\ m$

Distance of the enemy ship from the mountain $d'=6.10\times10^{2}\ m$

Initial velocity $v=2.55\times10^{2}\ m/s$

Angle = 74.9°

We need to calculate the horizontal component of initial velocity

Using formula of horizontal component

$v_{x}=v\cos\theta$

Put the value into the formula

$v_{x}=2.55\times10^{2}\cos74.9$

$v_{x}=66.42\ m/s$

We need to calculate the vertical component of initial velocity

Using formula of vertical component

$v_{y}=v\sin\theta$

Put the value into the formula

$v_{y}=2.55\times10^{2}\sin74.9$

$v_{y}=246.19\ m/s$

We need to calculate the time

Using formula of time

$t=\dfrac{d}{v_{x}}$

$t=\dfrac{2.46\times10^{3}}{66.42}$

$t=37.03\ sec$

We need to calculate the height of the shell on reaching the mountain

Using equation of motion

$H= v_{y}t-\dfrac{1}{2}gt^2$

Put the value in the equation

$H=246.19\times37.03-\dfrac{1}{2}\times9.8\times(37.03)^2$

$H=2397.4\ m$

We need to calculate the distance close to the peak

Using formula of distance

$H'=H-h$

Put the value into the formula

$H'=2397.4-1800$

$H'=597.4\ m$

Hence, The distance close to the peak is 597.4 m.

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3 years ago

As shown in Fig. 4, an ideal gas of monatomic molecules expands from its initial state A to a state B through an isobaric proces

cupoosta [38]

The picture is very blurry

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3 years ago

A temperature of 200°F is equivalent to approximately

aev [14]

<span>93.3°C
A temperature in Fahrenheit (°F) can be converted to Celsius (°C), using the formula
[°C] = ([°F] − 32) × 5⁄9. Here we have to convert a temperature of 200°F in to Celsius. Thus Subtract 32 from Fahrenheit and multiply by 5 then divide by 9 . That is (200°F - 32) × 5/9=168 × 5/9
=840/9
=93.333333333°C
= 93.3°C</span>

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3 years ago

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A container can hold a mass of 40 grams. If Jackson has a fake gold chain that has a density of 10 g/cm3 that occupies a space o

eimsori [14]

Use the formula M=D×V:

M=10 g/cm³ * 5 cm³ = 50 g

which is more than 40 grams, so the container cannot hold the chain.

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Your nerf dart gun is able to shoot a suction cup dart at a speed of 5 m/s. Your room is 3 meters across. You want to shoot your

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1,766 m according to my app. see foto.

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3 years ago