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1 year ago

Which pathway is the foundation for the majority of ecosystems and food chains on earth?

Physics

1 answer:

maw [93]1 year ago

6 0

Photosynthesis is the foundation of majority of ecosystems and food chains on earth .

What is photosynthesis ?

Photosynthesis is a process by which green plants , algae and certain bacteria turn sunlight ,carbon dioxide and water into food (sugar) and oxygen.

In this process light energy converted into chemical energy ,which is later used to fuel cellular activities .

Equation of photosynthesis :

6CO2 + 6H2O —> C6H12O6 + 6O2

Photosynthesis depends upon the factors like light intensity, the concentration of carbon dioxide ,temperature, water, and pollution .

photosynthesis takes place in the cell organelles called chloroplasts . these organelles contains a green coloured pigment called chlorophyll, which is responsible for the characteristic green colouration of the leaves.

What is ecosystem ?

An ecosystem is defined as a community of lifeforms in concurrence with components , interacting with each other .

It is the functional and structural unit of ecology where living organisms interact with each other and the surrounding environment .it is a chain or interaction between organisms and their environment.

Ecosystem term was first coined by A.G Tansley in 1935.

The structure of an ecosystem is characterised by the organisation of both biotic and abiotic components .

What is food chain?

A food chain refers to the order of events in an ecosystem ,where one living organism eats another organisms and later that organism is consumed by another larger organisms .the flow of nutrients and energy from one organism to another takes place at different trophic levels .ecosystem also explains the feeding pattern between living organisms.

Every levels of food chain is known as trophic level .

Food chain has 4 major parts like sun ,producers ,consumers,and decomposers.

Learn more about Photosynthesis here

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In this type of bond, electrons are lost or gained by atoms, and the atoms are held together by electrical attraction.

expeople1 [14]

<span>In Ionic type of bonding, electrons are lost (more protons than electrons and positive charge) or gained (more electrons than protons, still a negative charge) by atoms, and the atoms are held together by electrical attraction in the process. Covalent bondings are the sharing of electrons as well as partial bondings. Covalent bondings’ electrons have the same charges thus, there is no gaining or losing electrons in the process of sharing. Strong bondings are applicable only to Hydrogen (H) atoms. </span>

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3 years ago

1. What is the wavelength of a sound wave with a frequency of 50 Hz, if the Speed of sound is 343 m/s.

marshall27 [118]

1.6.86

2.59.04

3.3

Thats the answer I think

7 0

3 years ago

Using at least 3 to 4 complete content related sentences describe the first and second postulate of special relativity.

Andrew [12]

Nothing can travel faster than the speed of light. As such, perceptions of objects and time change as they approach light speed, but the laws of physics remain consistent regardless of speed. Objects will appear shortened and time will appear to slow down around an observer approaching near light speeds, but all quantities still exist as they did before and all causality is preserved, even if observers in different points or traveling at different speeds will report different things.

8 0

3 years ago

Read 2 more answers

The speed of light in vacuum is defined to be c = 299,792,458 m/s = 1 μ0ε0 . The permeability constant of vacuum is defined to b

Radda [10]

Explanation:

It is given that,

The speed of light in vacuum is, c = 299,792,458 m/s

The permeability constant of vacuum is, $\mu_o=4\pi\times 10^{-7}\ N.s^2/C^2$

Let $\epsilon_o$ is the permittivity of free space. The relation between $\mu_o,\epsilon_o\ and\ c$ is given by :

$c=\dfrac{1}{\sqrt{\mu_o\epsilon_o}}$

$\epsilon_o=\dfrac{1}{c^2u_o}$

$\epsilon_o=\dfrac{1}{(299792458\ m/s)^2\times 4\pi\times 10^{-7}\ N.s^2/C^2}$

$\epsilon_o=8.85\times 10^{-12}\ C^2/N.m^2$

Hence, this is the required solution.

3 0

3 years ago

Read 2 more answers

Four long wires are each carrying 6.0 A. The wires are located

Firdavs [7]

Answer:

$B_T=2.0*10^-5[-\hat{i}+\hat{j}]T$

Explanation:

To find the magnitude of the magnetic field, you use the following formula for the calculation of the magnetic field generated by a current in a wire:

$B=\frac{\mu_oI}{2\pi r}$

μo: magnetic permeability of vacuum = 4π*10^-7 T/A

I: current = 6.0 A

r: distance to the wire in which magnetic field is measured

In this case, you have four wires at corners of a square of length 9.0cm = 0.09m

You calculate the magnetic field in one corner. Then, you have to sum the contribution of all magnetic field generated by the other three wires, in the other corners. Furthermore, you have to take into account the direction of such magnetic fields. The direction of the magnetic field is given by the right-hand side rule.

If you assume that the magnetic field is measured in the up-right corner of the square, the wire to the left generates a magnetic field (in the corner in which you measure B) with direction upward (+ j), the wire down (down-right) generates a magnetic field with direction to the left (- i) and the third wire generates a magnetic field with a direction that is 45° over the horizontal in the left direction (you can notice that in the image attached below). The total magnetic field will be:

$B_T=B_1+B_2+B_3\\\\B_{T}=\frac{\mu_o I_1}{2\pi r_1}\hat{j}-\frac{\mu_o I_2}{2\pi r_2}\hat{i}+\frac{\mu_o I_3}{2\pi r_3}[-cos45\hat{i}+sin45\hat{j}]$

I1 = I2 = I3 = 6.0A

r1 = 0.09m

r2 = 0.09m

$r_3=\sqrt{(0.09)^2+(0.09)^2}m=0.127m$

Then you have:

$B_T=\frac{\mu_o I}{2\pi}[(-\frac{1}{r_2}-\frac{cos45}{r_3})\hat{i}+(\frac{1}{r_1}+\frac{sin45}{r_3})\hat{j}}]\\\\B_T=\frac{(4\pi*10^{-7}T/A)(6.0A)}{2\pi}[(-\frac{1}{0.09m}-\frac{cos45}{0.127m})\hat{i}+(\frac{1}{0.09m}+\frac{sin45}{0.127m})]\\\\B_T=\frac{(4\pi*10^{-7}T/A)(6.0A)}{2\pi}[-16.67\hat{i}+16.67\hat{j}]\\\\B_T=2.0*10^-5[-\hat{i}+\hat{j}]T$

5 0

3 years ago