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inessss [21]
3 years ago
8

Use Hooke's Law and Newton's 2nd Law to derive a formula for the acceleration of an object of mass m on a frictionless surface w

hich is attached to a spring with a constant k which is stretched a distance L. The acceleration should be in terms of m, k, and L.
Physics
1 answer:
kramer3 years ago
4 0

Answer:

a = kL/m

Explanation:

Here we can use Hooke's Law to find out the force applied on the system. Hooke's Law states that when a spring is stretched by some force, the force applied is directly proportional to the displacement of spring. The formula is given as:

F = kL

Now, the Newton's Second Law of motion states that whenever an unbalanced force is applied to a body it produces an acceleration in the body, in its own direction. So, the force is given by the formula:

F = ma

Comparing both the forces, we get:

kL = ma

<u>a = kL/m</u>

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How does an executive order differ from a statue?
ICE Princess25 [194]

Answer: Executive Order on Protecting American Monuments, Memorials, and Statues against our country are public monuments, memorials, and statues.

Explanation: learned it last week

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3 years ago
If you were to choose one, which of Earth's spheres is the most important, and why?
Molodets [167]

Earth's land makes up the geosphere.

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7 0
3 years ago
A 0.9 µF capacitor is charged to a potential difference of 10.0 V. The wires connecting the capacitor to the battery are then di
jeyben [28]

Answer:

3.6μF

Explanation:

The charge on the capacitor is defined by the formula

q = CV

because the charge will be conserved

q₁ = C₁V₂

q₂ = C₂V₂ where C₂ V₂ represent the charge on the newly connected capacitor  and the voltage drop across the two capacitor will be the same

q = q₁ + q₂ = C₁V₂ + C₂V₂

CV = CV₂ + C₂V₂

CV - CV₂ = C₂V₂

C ( V - V₂) = C₂V₂

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7 0
3 years ago
The answer would be ?
Cerrena [4.2K]

Answer:

D. demand; increased

Explanation:

Demand is how much people want it.

4 0
3 years ago
An object that completes 20 vibrations in 10 seconds has a frequency of
nika2105 [10]

Answer:

<em> The object has frequency of 2 Hz and time period of 0.5 s.</em>

Explanation:

<em>Frequency</em> is defined as number of oscillation per second ie back and forth swings done in single second.

Here it is given that the object oscillates 20 times in 10 seconds.

So f = \frac{20}{10} = 2Hz

The <em>time period</em> is defined as time taken by the object to complete one full oscillation.

T = \frac{1}{f}

T= \frac{1}{2} =0.5 s

<em>Thus the object has frequency of 2 Hz and time period of 0.5 s.</em>

7 0
3 years ago
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