HELP MEEEEE Write 77% as a decimal.

Mathematics

2 answers:

kicyunya [14]3 years ago

7 0

Answer:0.77

Step-by-step explanation:

Ainat [17]3 years ago

4 0

77% as a decimal is 0.77 hundredths

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Solve 4 + (-3) - 2 x (-6) A. -11 B. 12 C. -10 D. 13

Gennadij [26K]

Answer:

Step-by-step explanation:

Using PEMDAS you start with multiplication first, so -2 multiplied by -6, which is positive 12. Then you go from left to right, so 4 +-3, or 4-3, which is 1. Then 1-12 is -11. So your final answer is A, -11.

8 0

3 years ago

I need to know the answer

Ainat [17]

Answer:

a) 5

b) 20

c) 28

d) 10

Step-by-step explanation:

a) 7-2=5

b) 2(7)+3(2)

= 14+6

= 20

c) 2(7)(3)= 28

d) (7-2)^2

= (14-4)

= 10

4 0

2 years ago

Read 2 more answers

Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the func

mote1985 [20]

Solution:

The given Polynomial is :

$f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})$

By Rational Root theorem the of Zeroes of the Polynopmial are:

$\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4$

But , $f(\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4)\neq 0$

So, no root of this polynomial is real.

Therefore, All the four roots of Polynomial are imaginary.

So, we can't say whether the number k=2, is an upper or lower bound of the polynomial $f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})$ .