We are given the rate law, so we can substitute the given values for the rate constant and the concentrations of the reactants to solve for the rate of reaction. Since rate = k [NH4+][NO2-]:
rate = (2.7 x 10^-4 / M-s)(0.050 M)(0.25 M) = 3.375 x 10^-6 M/s
Answer :
A car stopped at the top of a hill
Explanation :
Definition of potential energy : energy stored that depends upon the relative position of various parts of a system
Work is measured in joules. hope this helps!
The reaction equation is first order with respect to [H+]
when PH1 = -㏒[H+]1 so, when PH = 6
So by substitution:
∴ 6 = -㏒[H+]1
∴[H+]1 = 1 x 10^-6
and when PH2 = -㏒[H+]2 so, when PH2 = 2
so by substitution:
∴ 2 = -㏒[H]2
∴[H]2 = 1 x 10^-2
So the rate of reaction changes by the factor of:
[H2]2/[H]1 = (1 x 10^-2) / (1 x 10^-6) = 10000
It is 10000 times faster when PH decreases from 6 to 2
Answer:
energy of photon=1.824ev
Explanation:
given wavelength of ligt=6.8×10⁻⁷m=6800A⁰
energy of photon(E)=hc/λ;
and for simplicity
E=12400/λ
where λ is aken in angstorm
and energy in ev
E=12400/6800ev
E=1.824ev=energy of photon
