To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency

$ma = \text{Mass}\times \text{Acceleration}$

$ma = kg \cdot \frac{m}{s^2}$

At the same time we have that

$\frac{1}{2}mv^2 = \text{Mass}\times \text{Velocity}^2$

$\frac{1}{2}mv^2 = kg ( \frac{m}{s})^2$

$\frac{1}{2}mv^2 = kg \cdot \frac{m^2}{s^2}$

Therefore there is not have same units and both are not consistent and the correct answer is B.

5 0

3 years ago

A galvanometer is used as a

agasfer [191]

Answer:

detecting and indicating an electric current

4 0

3 years ago

(I NEED THIS ANSWERED NOW PLEASE)

VMariaS [17]

Answer:

Zeros that follow non-zero numbers and are also to the right of a decimal point are significant.

Explanation:

For example:

0.300 has 3 significant figures.

5.400 has 4 significant figures.

4 0

2 years ago