Answer:
a) tires rubbing, b) the weight has a component parallel to the floor
c) he child's back support, d) The tension of the rope and weight
Explanation:
In this exercise, we are asked to indicate the origin of the forces for the centripetal movement parallel to the rope, e) gravitational force
a) When a car turns, the centripetal force has two origins
* The tires rubbing against the road
* If the road has a lean angle, the component of the weight directed towards the center of the circle also contributes to the centripetal force.
b) the child in general has some degree of inclination with respect to the post, for which the weight has a component parallel to the floor that is responsible for the centripetal movement of the system
c) The bench rotates together with the carousel, so the child's back support is the response to the centripetal force
d) The tension of the rope has two components: the component perpendicular to the movement and the component of the weight (parallel to the rope) the difference of these two forces is the centripetal force
e) The gravitational force of the sun on the earth is what creates the centripetal motion
Everything would be more advanced and logical while the past people really just tried to survive.
Answer:
Ender's mass = 2.25 kg
Explanation:
using law of conservation of momentum .
since there is inelastic collision
given.
Answer:
Explanation:
Total frictional force on boxes
= total weight x coefficient of friction
= ( 11 + 7 ) x 9.8 x .02 = 3.53 N
Net force on boxes
= 8.9 - 3.53
= 5.37 N
acceleration = 5.37 /( 11 + 7 )
= 0.3 m / s ²
b ) Let us consider movement of block A ( 11 kg )
acceleration a = .3 m/s²
friction force on block A
11 X 9.8 X .02
= 2.156 N
Net force on block A
8.9 - friction force - reaction force by block B
= 8.9 - 2.156 - F_ c
force = mass x acceleration
8.9 - 2.156 - F_ c = 11 x .3
F_ c = 3.444 N
c )
If force is applied from the side of box B
We consider all forces on box B
frictional force on it
= 7 x 9.8 x .02
= 1.372 N
Net force on it
8.9 - 1.372 - F_c
force = mass x acceleration
= 8.9 - 1.372 - F_c = 7 x .3 ( Acceleration of box B will be the same that is 0.3 m/s² )
F_c = 5.428 N
Answer:
f = 7.11 Hz
Explanation:
Given that,
The amplitude of object in SHM, A = 0.02 m
The maximum acceleration of the object, a = 40 m/s²
We need to find the frequency of the system.
The maximum acceleration of the object in SHM is given by :
Where is angular frequency
We know that,
So, the frequency of the system is 7.11 Hz.