Hello,
y=sin²(cos(2x))
y'=2*sin(cos(2x))*cos(cos(2x))*(-sin(2x)*2)
= -4*sin(cos(2x))*cos(cos(2x))*sin(2x)
T= Mins
1 hour = 60 mins
60 x 6 = 360
360 - T = x
X= How many minutes he has remaining
This has both a horizontal and a vertical asymptote. There are no slant (oblique) asymptotes cuz the degree of the numerator is not higher than that of the denominator. If the degree of the numerator is less than the degree of the denominator, which is our case here, then the horizontal asymptote is 0. But we also have a vertical asymptote, which occurs where the denominator = 0. We all know that we break every rule known to mankind if we try to divide by 0, so there also a vertical asymptote at x = 2.
