Ask question

Ask question

All categories

3 years ago

15

(a) Find the size of the smallest detail observable in human tissue with 20.0-MHz ultrasound. (b) Is its effective penetration d

epth great enough to examine the entire eye (about 3.00 cm is needed)? (c) What is the wavelength of such ultrasound in 0ºC air?

1 answer:

koban [17]3 years ago

5 0

Answer:

(a) λ=77×10⁻⁶m

(b)Yes its enough to examine entire eye,

(c)λ=16.65μm.

Explanation:

The ultrasonic sound are used to detect problems in human body by using device consisting of transmitter and detector .

The speed of sound in human tissue is 1540m/s.

The wavelength of sound is 20MHz.

(a) let the velocity of sound in human tissue is v = 1540m/s.

v=fλ

λ= $\frac{v}{f}$ = $\frac{1540}{20MHz}$ = 77×10⁻⁶m

λ=77×10⁻⁶m

(b) we can scan effectively upto the depth of about 500λ

500λ=500× (77×10⁻⁶)= 3.85cm

Yes its enough to examine entire eye,

(c) In air the velocity of sound is 331m/s.

λ= $\frac{v}{f}$ = $\frac{331 m/s}{20Mhz}$ = 16.65μm

λ=16.65μm.

You might be interested in

Most reactive non-metals in order?

kompoz [17]

Nonmetals often share or gain electrons. The nonmetals in the periodic table increases as you move to the right and decreases as you go down. This is because, the smaller the atom, the reactive it gets due to less electron attached to the orbits of the atom. The reactivity of nonmetals is arranged in decreasing order. <span>
Carbon
</span> Nitrogen
Oxygen
Fluorine
Phosphorus <span>
Sulfur</span>
Chlorine <span>
Selenium</span> <span>
Bromine</span> <span>
Iodine</span>

5 0

3 years ago

If the net force acting on an object is 0 N, you can be sure thr forces acting on the object are,

Bas_tet [7]

Answer:

A. Balanced

Explanation:

7 0

2 years ago

What are the positive impacts of Genetically Modified Crops?

xeze [42]

Answer:

The crops will have the ability to be resistant to certain diseases

7 0

2 years ago

Read 2 more answers

Problem One: A beam of red light (656 nm) enters from air into the side of a glass and then into water. wavelength, c. and speed

Ivanshal [37]

Answer:

Part a)

$f_w = f_g = 4.57 \times 10^{14} Hz$

Part b)

$\lambda_w = 492 nm$

$\lambda_g = 437.3 nm$

Part c)

$v_w = 2.25 \times 10^8 m/s$

$v_g = 2.0 \times 10^8 m/s$

Explanation:

Part a)

frequency of light will not change with change in medium but it will depend on the source only

so here frequency of light will remain same in both water and glass and it will be same as that in air

$f = \frac{v}{\lambda}$

$f = \frac{3 \times 10^8}{656 \times 10^{-9}}$

$f = 4.57 \times 10^{14} Hz$

Part b)

As we know that the refractive index of water is given as

$\mu_w = 4/3$

so the wavelength in the water medium is given as

$\lambda_w = \frac{\lambda}{\mu_w}$

$\lambda_w = \frac{656 nm}{4/3}$

$\lambda_w = 492 nm$

Similarly the refractive index of glass is given as

$\mu_w = 3/2$

so the wavelength in the glass medium is given as

$\lambda_g = \frac{\lambda}{\mu_g}$

$\lambda_g = \frac{656 nm}{3/2}$

$\lambda_g = 437.3 nm$

Part c)

Speed of the wave in water is given as

$v_w = \frac{c}{\mu_w}$

$v_w = \frac{3 \times 10^8}{4/3}$

$v_w = 2.25 \times 10^8 m/s$

Speed of the wave in glass is given as

$v_g = \frac{c}{\mu_g}$

$v_g = \frac{3 \times 10^8}{3/2}$

$v_g = 2 \times 10^8 m/s$

4 0

3 years ago

Please help (choose a b or c)

Dafna11 [192]

I GEUSS A and COM is correct answer to this question

3 0

3 years ago

Read 2 more answers