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steposvetlana [31]
3 years ago
7

In an electrolytic cell, to which electrode will a positive ion migrate and undergo reduction? the anode, which is negatively ch

arged the anode, which is positively charged the cathode, which is negatively charged the cathode, which is positively charged
Physics
2 answers:
ahrayia [7]3 years ago
4 0
The reaction of reduction always undergoes with the cathode, the positive ion will migrate towards the cathode with the negative charge whilst the anode always has oxidation reaction. These two types of reaction does not change.
sveticcg [70]3 years ago
3 0

Answer:

the cathode, which is negatively charged

Explanation:

In an electrolytic cell, there are two electrodes; the anode and the cathode. The anode is positively charged while the cathode is negatively charged.

Oxidation occurs at the anode as the positive ions loose electrons. The electrons lost at the anode travels via a conductor to the cathode. Positive ions migrate to the cathode, accept these electrons and become reduced.

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Do all of them please and explain
kondaur [170]

At 305 and 309 it was negative because it is going down


at 300 and 301 and 305 it was positive because its going up


at 302/303/304/306/309 she wasn't accelerating at all because it is staying the same

5 0
3 years ago
Read 2 more answers
It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s 2 . Find the magnitude of acce
shepuryov [24]

This Question is not complete

Complete Question:

a. A hawk flies in a horizontal arc of radius 11.3 m at a constant speed of 5.7 m/s. Find its centripetal acceleration.

Answer in units of m/s2

b. It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s2. Find the magnitude of acceleration under

these new conditions.

Answer in units of m/s2

Answer:

a. 2.875m/s²

b. 3.172m/s²

Explanation:

a. The formula for centripetal acceleration = (speed²) ÷ radius

Centripetal acceleration = (5.7m/s)²÷ 11.3m

Centripetal acceleration = 2.875m/s²

b. Magnitude of acceleration can be calculated by finding the sum of the vectors for the both the centripetal acceleration and the increase in the speed rate.

Centripetal acceleration ( acceleration x) = 2.875m/s²

Increase in the speed rate ( acceleration n) = 1.34m/s²

Magnitude of acceleration = √a²ₓ + a²ₙ

=√( 2.875m/s²)²+ (1.34m/s²)²

= √ 10.06m/s²

= 3.172m/s²

3 0
3 years ago
Read 2 more answers
During soccer practice, Maya kicked a soccer ball 37° off the ground at 25 m/s. What was the ball's speed 2.2 s after she kicked
ki77a [65]

<u>Answer</u>

3.44 m/s


<u>Explanation</u>

The motion apply the equations of Newton's law of motion. The ball is acceleration is -9.8 m/s² (acceleration due to gravity. It is negative because the ball is going against gravity, so it is decelerating).

The first equation of Newton's law of motion is;

V = U + at

Where V is the final velocity, U is the initial velocity, a is acceleration and t the time taken.

V = 25 + (-9.8 × 2.2)

    = 25 - 21.56

     = 3.44 m/s

5 0
3 years ago
Which of the following is a force or motion that
faltersainse [42]

Answer: this answer is D. That's what I think it is

Explanation:

7 0
2 years ago
A plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy. Which organelle is m
Nadya [2.5K]

The chloroplast of the cell is most likely damaged if the plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy.

The chloroplast is the structure inside the leaf cell that is known for capturing light energy from the sun.

This light energy is then used to make food that has chemical energy. If a plant cell has a damaged chloroplast or the chloroplast is removed, then it will no longer be able to trap the light energy. As a result, the process of photosynthesis will not occur in the plant cell. The plant cell will not be able to make the chemical energy required for functioning.

To learn more about chloroplast, click here:

brainly.com/question/1741612

#SPJ4

8 0
1 year ago
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