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steposvetlana [31]
3 years ago
7

In an electrolytic cell, to which electrode will a positive ion migrate and undergo reduction? the anode, which is negatively ch

arged the anode, which is positively charged the cathode, which is negatively charged the cathode, which is positively charged
Physics
2 answers:
ahrayia [7]3 years ago
4 0
The reaction of reduction always undergoes with the cathode, the positive ion will migrate towards the cathode with the negative charge whilst the anode always has oxidation reaction. These two types of reaction does not change.
sveticcg [70]3 years ago
3 0

Answer:

the cathode, which is negatively charged

Explanation:

In an electrolytic cell, there are two electrodes; the anode and the cathode. The anode is positively charged while the cathode is negatively charged.

Oxidation occurs at the anode as the positive ions loose electrons. The electrons lost at the anode travels via a conductor to the cathode. Positive ions migrate to the cathode, accept these electrons and become reduced.

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4 years ago
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You use 8x binoculars were used on a warbler (14cm long) in a tree 18cm away. What angle (in degrees) does the image of the warb
mafiozo [28]

Answer:

The angle it subtend on the retina is  \theta_z = 0.44586^o    

Explanation:

From the question we are told that

     The length of the warbler is  L = 14cm = \frac{14}{100} = 0.14m

      The distance from the binoculars is    d = 18cm = \frac{18}{100} = 0.18m

        The magnification of the binoculars is  M =8

Without the 8 X binoculars the  angle made with the angular size of the object  is mathematically represented as

          \theta = \frac{L}{d}

        \theta  = \frac{0.14}{0.18}

           = 0.007778 rad

Now magnification can be represented mathematically as

         M = \frac{\theta _z}{\theta}

Where \theta_z is the angle the image of the warbler subtend on your retina when the   binoculars i.e the  binoculars zoom.

So

      \theta_z = M * \theta

=>    \theta_z =8 * 0.007778

            = 0.0622222224

Generally the conversion to degrees can be mathematically evaluated as

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              \theta_z = 0.44586^o  

7 0
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